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IgorC [24]
3 years ago
11

5n + 2n + 6 = 4n - 21

Mathematics
2 answers:
sergiy2304 [10]3 years ago
8 0

5n+2n+6=4n-21 group like terms on left side

7n+6=4n-21subtract 6 from both sides

7n=4n-27 subtract 4n from both sides

3n=27 divide both sides by 3

n=9

Airida [17]3 years ago
7 0
Combine like terms
7n + 6 = 4n - 21
3n = -27
Divide by 3
n = -27/3 (u can simplify)
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2 more and I’m done thank y’all so much sorry I’m dumb and in 8th grade LOL
kotegsom [21]

9. -5(4+6r)

-20-30r

-20-30(4)=-20-120=-140

10. -9-n/3

-9-9/3=-9-3=-12

answers: -140, -12

7 0
3 years ago
Read 2 more answers
Maggie is flying a kite and lets out
seraphim [82]

Answer:

5

Step-by-step explanation:

Easy

4 0
3 years ago
A bolt falls off an airplane at an altitude of 500 m. How long will it take the bolt to reach
Rudik [331]

Answer:

t = sqrt(500/4.9) =~ 10.1 seconds/ Answer: 10.1015 seconds (this is approximate)

Step-by-step explanation:

Use 4.9t^2 + v0t = s

a) A bolt falls off an airplane at an altitude of 500 m. Approximately how long does it take the bolt to reach the ground?

s = 4.9t^2 + v0t = 500

4.9t^2 = 500

t = sqrt(500/4.9) =~ 10.1 seconds

Part A)

v = initial velocity = 0

s = 500 = vertical distance the object travels (from plane to ground)  

Plug in the given values and solve for t

4.9t^2 + v*t = s

4.9t^2 + 0*t = 500

4.9t^2 + 0 = 500

4.9t^2 = 500

t^2 = 500/4.9

t^2 = 102.04081632653

t = sqrt(102.04081632653)

t = 10.101525445522

t = 10.1015

Answer: 10.1015 seconds (this is approximate)

8 0
3 years ago
find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the large
katrin2010 [14]

A generic odd number can be written as

2k+1,\quad k \in \mathbb{Z}

Since there is an odd number every two numbers, three consecutive odd numbers will be

2k+1,\quad 2k+3,\quad 2k+5

Now let's make up the equations: the sum of the first two is

(2k+1)+(2k+3)

And 27 less than 3 times the largest is

3(2k+5)-27

These two must be the same, so we have

(2k+1)+(2k+3)=3(2k+5)-27 \iff 4k+4 = 6k+30-27 \iff 4k+4=6k+3

Subtracting 4k and 3 from both sides gives

1=2k \iff k=\dfrac{1}{2}

Which means that the problem has no solution.

To confirm this hypothesis, we can observe that, on the left hand side, we have the sum of two odd numbers, which is even

On the right hand side, we have an odd number, multiplied by 3 (still odd), take away 27 (still odd).

So, the left hand side is even, and the right hand side is odd. They can't be the same number.

7 0
4 years ago
Solve the system of equations by substitution.<br> X=-4y<br> X+5y=2
Eduardwww [97]
X= -4y  let this be equation 1
x+5y=2 let this be equation 2

substitute equation 1 in 2

-4y + 5y = 2

y=2

substitute the value of y in equation 1

x= -4y
x= -4(2)
x= -8
5 0
3 years ago
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