Answer:
curved ramp
or quadrant circle map
Step-by-step explanation:
Answer:
Part 5.1.1:

Part 5.1.2:

Step-by-step explanation:
We are given that:

Part 5.1.1
Recall that:

Let θ = 2<em>A</em>. Hence:

Square the original equation:

Hence:

Subtract:

Take the square root of both sides:

Since 0° ≤ 2<em>A</em> ≤ 90°, cos(2<em>A</em>) must be positive. Hence:

Part 5.1.2
Recall that:

We can use the third form. Substitute:

Solve for cosine:

In conclusion:

(Note that since 0° ≤ 2<em>A</em> ≤ 90°, 0° ≤ <em>A</em> ≤ 45°. Hence, cos(<em>A</em>) must be positive.)
You can start by rewriting the equation so that the right side equals zero. Add

and

to both sides.

You can now use the quadratic equation (below), where

and

, to find solutions. Plug in these values for

and

into the equation and simplify.




The final answer is the combination of both solutions.

Or approximately...