Solve for x

Thom needs 3/4 yard of brown fabric, 2/4 yard of blue fabric, and 3/4 yard of green fabric to make some costumes for a play.

kherson [118]

Answer:

Step-by-step explanation:

Hey there!

I think that some of the content in your question is missing so I will be solving for how much yards of fabric is needed in total

Since all of the fractions have common denominators, we can comfortably add them together

3/4+3/4+2/4 is 8/4

8/4 can be simplied to 2

So the total amount of yards of fabric Thom needs in total is 2 yards

5 0

2 years ago

Examine the following three premises: i. All kids who have a smartphone play mobile legends.

atroni [7]

Answer:

The increasing number of students who are hooked on playing online mobile games (OMG) is alarming. As such, this study was realized to address the problem. This study assessed the gaming profile towards OMG and its relation to the academic performance of the engineering students of Eastern Visayas State University Tanauan Campus (EVSUTC). Specifically, the study investigated the correlation between student's number of hours spent on playing OMG (at school and home), commonly played OMG (at school and home), reasons for playing OMG and attitudes on playing OMG with academic performance utilizing Eta and Pearson r correlation analyses. A random sample of 134 student respondents were selected through purposive sampling of those who are playing OMG using their mobile phones. Descriptive correlational research design was utilized and a validated survey instrument was employed to gather the needed information. The findings revealed that majority of the students played mobile legends and spent mostly 2 hours playing OMG for a reason of boredom. The overall attitudes of the students on playing OMG were interpreted as Less Favorable (M=2.58, SD=1.13). Out of the independent variables being set in the study, the number of hours spent on playing OMG at home (r=-0.188, p=0.039) and commonly played OMG at school (r=0.203, p=0.045) were found significantly correlated with student's academic performance. Hence, the students' time spent on playing OMG at home and the type of games that students played at school have significant bearing to their academic performance. As such, delimiting student's usage of internet can be made to address the problem.

3 0

1 year ago

A student bought some pens at 8 each and some pencils at 31.50 each. If the total

Wittaler [7]

Step-by-step explanation:

Letthenumberofpensbexand

numberofpencilsbey

then

x+y=16ory=16−x

andtheirvalue

8x+1.5y=50

8x+(

2

3

)(16−x)=50

8x+24−(

2

3

)x=50

8x−(

2

3

)x=50−24

(

2

13x

)=26∴x=4

theny=16−x=16−4=12

5 0

2 years ago

Select two values of x that are roots of this equation (picture included)<br><br> x^2+2x-5=0

WINSTONCH [101]

Step-by-step explanation:

A and C are correct options

7 0

2 years ago

Read 2 more answers

A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us

Zanzabum

Answer:

Step-by-step explanation:

Hello!

The objective of the study is to determine whether the magnets are effective in treating pain. For these two independent groups of individuals with equal affections were randomly sampled, one was treated with magnets and the other group of individuals, call it control group, was treated with a placebo treatment.

The information for both samples is:

X₁: pain measurement using a visual analog scale after the individual received magnet treatments.

X₁~N(μ₁;σ₁²)

n₁= 20

X[bar]₁= 0.46

S₁= 0.93

X₂: pain measurement using a visual analog scale of an individual of the control groups.

X₂~N(μ₂;σ₂²)

n₂= 20

X[bar]₂= 0.41

S₂= 1.26

The claim is that the pain reductions of the control group have more variation than the pain reductions of the target group. If it's so then we could suspect that the population variance of the control group, σ₂², will be greater than the population variance of the magnet group, σ₁².

To test the relationship between these two population variances you have to conduct a variance ratio test using the Snedecors F statistic.

The hypotheses are:

H₀: σ₂² ≤ σ₁²

H₁: σ₂² > σ₁²

α: 0.05

$F= (\frac{S_2^2}{S_1^2}) * (\frac{Sigma_2^2}{Sigma_1^2} )~~ F_{(n_2-1);(n_1-1)}$

This hypothesis test is one-tailed to the right, there is only one critical value:

$F_{(n_2-1);(n_1-1); 1 - \alpha } = F_{19;19; 0.95}= 2.17$

The decision rule for the test is:

If $F_{H_0}$ ≥ 2.17, then the decision is to reject the null hypothesis.

If $F_{H_0}$ < 2.17, then the decision is to not reject the null hypothesis.

$F_{H_0}= \frac{S_2^2}{S_1^2}*\frac{Sigma_2^2}{Sigma_1^2} = \frac{(1.26)^2}{(0.93)^2} * 1$

$F_{H_0} = 1.835 = 1.84$

Since the calculated value of F is less than the critical value, the decision is to reject the null hypothesis. So using a 5% significance level the decision is to not reject the null hypothesis, you can conclude that the population variance of the pain reduction of the control group is less or equal than the population variance of the pain reduction on individuals treated with magnets.

I hope it helps!

3 0

3 years ago