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3 years ago

PLEASE HELP ME ASAP! ILL GIVE YOU BRAINLEST!

Mathematics

1 answer:

Helen [10]3 years ago

4 0

Answer:

13/99

Step-by-step explanation:

First convert the expression, turn 13 into 13/1: 13/1 × 1/99

Next you multiply: 13/1 × 1/99 = 13/99

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What is each of the expression written using each base only once? 10^10 x 10^10

aleksklad [387]

The answer is 10 thousand

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3 years ago

Solve the equation.

Levart [38]

Answer:

x=34

Step-by-step explanation:

6 - ( x-7) ^ 1/3 = 3

Subtract 6 from each side

6-6 - ( x-7) ^ 1/3 = 3-6

- ( x-7) ^ 1/3 = -3

Divide each side by a negative

( x-7) ^ 1/3 = 3

Cube each side

( x-7) ^ 1/3 ^3 = (3)^3

x-7 = 27

Add 7 to each side

x-7+7 = 27+7

x = 34

Check

6 - ( 34-7) ^ 1/3 = 3

6 - (27^1/3 = 3

6 -3 =3

3=3

Good solution

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4 years ago

Zuri is stuck in traffic. She notices that she only drove 3 miles in 15 minutes.

makkiz [27]

Answer:

0.2

Step-by-step explanation:

3/15=0.2

6 0

3 years ago

First, she walks 4 blocks

antoniya [11.8K]

Answer:.

W. T. F.

it has nothing to do with a dog!?!?!?!?!!?!?!?!?!?!?

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4 years ago

A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$

The probability that at most 12 ties are too tight is P=1.

5 0

3 years ago