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Andrej [43]
2 years ago
13

Find the equations of the tangents to y=x^2 which pass through the point (2,3).

Mathematics
1 answer:
algol [13]2 years ago
6 0

Answer: The equations of the tangents that pass through

y  =  -x- 1 and

y = 11x -25

Step-by-step explanation: The gradient of the tangent to a curve at any particular point is given by the derivative of the curve at that point. So for our curve (the parabola) we have

y= x^2 +x

Differentiating wrt  x we get:

dy/dx = 2x +1

Let P (a, B)  be any generic point on the curve. Then the gradient of the tangent at P is given by:

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Harrizon [31]

Answer:

equation; P=A(1+r/n)^nt

P=principal amount

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r= interest rate in decimals

n=number of times compounded

t=time in years

P=1000(1+0.16/12)^12(5)= $2213.8 rounded

Step-by-step explanation:

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3 years ago
Which statements can be concluded from the diagram and used to prove that the triangles are similar by the SAS similarity theore
velikii [3]

Answer:

RS/VU=ST/UT and ∠S≅∠U

Step-by-step explanation:

we know that

The <u>Side-Angle-Side Similarity Theorem </u>states that: If two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar

In this problem the included angle is

∠S≅∠U

therefore

side RS must be proportional to side VU  and side ST must be proportional to side UT

so

RS/VU=ST/UT

<em>Verify</em>

substitute the given values

12/6=16/8

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6 0
2 years ago
Read 2 more answers
Match each simplified form to it's equivalent radical expression. Tiles: 4√3, 3 3√2, 2 3√3, 3√5
lbvjy [14]

Answer:

Step-by-step explanation:

Given the following simplified expressions:

4√3, 3 3√2, 2 3√3, 3√5

It's radical equivalent is :

4√3 = √4² * √3 = √16 * √3 = √16*3 = √48

3 3√2 = 3 * √3² * √2 = √9 * √2 = √9*2 = 3√18

2 3√3 = 2 * √3² * √3 = √9 * √3 = √9*3 = 2√27

3√5 = √3² * √5 = √9 * √5 = √9*5 = √45

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3 years ago
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AysviL [449]
1) 1
2) PA: between 2 and 3.
2) PB: Unsure about it.
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2 years ago
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