1. (t-5)^2+3=t^2-10t+12+3=t^2-10t+15.
2. (a+h)^2+3=a^2+2ah+h^2+3
(a^2)+3=a^2+3. Subtracting, we get h^2+2ah.
3. (a^2)+3=a^2+3
(a-h)^2+3=a^2-2ah+h^2+3. Subtracting, we get 2ah-h^2.
M would stand for 5/8 because 1/2 is equal to 4/8. So what you would do is 1/8 + 1/2 and you get 5/8.
Answer: A
Step-by-step explanation:

Answer:
(A) 40%
(B) 60%
Step-by-step explanation:
Given:
Total number of cars = 200
Cars in parking lot on Friday = 120
Total number of cars = Total cars on Friday + Total cars on Saturday.
⇒ 200 = 120 + Total cars on Saturday.
⇒ Total cars on Saturday = 200 - 120 = 80
So, 80 cars were in parking lot on Saturday.
(A)
Percentage of cars in parking lot on Friday is given as:

Therefore, 60% of the cars were in the parking lot on Friday.
(B)
Now, since 60% of the cars were parked on Friday, the remaining percent will be on Saturday.
Therefore, percentage of cars in parking lot on Saturday = 100% - 60% = 40%. This can be verified with the same formula used in part (A).

Answer:
Step-by-step explanation:
1,2,4,8,16,32,64