Because when mixed the food coloring spreads to the less dense parts of the water cup.
Question: <em>What is the hybridization of each carbon and oxygen atoms in vitamin C?</em>
Answer:
1. To decide the hybridization of a carbon, look at how many atoms are attached to it (including the hydrogens that may be unwritten). If there are 4 total atoms attached (all with single bonds), the carbon must have sp3 orbitals (there are 4 of them). If 3, then sp2. If 2, then sp. Carbon can't be sp3d or sp3d2 hybridized because carbon is in the 2nd period of the periodic table and doesn't possess any d orbitals to hybridize.
2. Not sure what this question means. Did you mean to type just C-C bonds? If so, just count the number of bonds between 2 carbon atoms!
3. Use VSEPR. The bond angle is as great as possible, based on the repulsion of the valence electron pairs (both bonded and lone). This is also related to hybridization. sp3 hybrid orbitals are 109.5 degress apart, sp2 is 120, sp is 180.
4. See part 1. Determine the hybridization of both C4 and C5. The overlap of an orbital from each carbon is what forms the sigma bond.
Answer: Since this is merely a Physical Change, it is improper to write it as a chemical equation.
The volume of one mole of gas is 22.4 liters at 0 °C and 760 Torr. The volume of the given condition can be calculated using:
(PV)/T = constant
(P₁V₁)/T₁ = (P₂V₂)/T₂
(760 * 22.4)/273 = (792 * V₂) / 321.7
V₂ = 25.3 Liters
The Mr of He = 4
The Mr of Ne = 20
Density of He = 4/25.3 = 0.1581 g/L
Density of Ne = 20/25.3 = 0.7905 g/L
Let x be the fraction of Ne
1 - x is the fraction of He
avg density = sum[(mole fraction * Mr)/V]
0.6048 = (20x + 4(1 - x))/25.3
x = 0.70
