Acceleration<span> is a vector quantity that is defined as the rate at which an object changes its velocity. An object is </span>accelerating<span> if it is changing its velocity. It can be calculated by the expression:
a = v2 - v1 / t
From the given in the problem, we can solve for v2, the final velocity:
3 = v2 - 0 / 300
v2 = 900 m/s</span>
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Answer:
30.63 m
Explanation:
From the question given above, the following data were obtained:
Total time (T) spent by the ball in air = 5 s
Maximum height (h) =.?
Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:
Total time (T) spent by the ball in air = 5 s
Time (t) taken to reach the maximum height =.?
T = 2t
5 = 2t
Divide both side by 2
t = 5/2
t = 2.5 s
Thus, the time (t) taken to reach the maximum height is 2.5 s
Finally, we shall determine the maximum height reached by the ball as follow:
Time (t) taken to reach the maximum height = 2.5 s
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =.?
h = ½gt²
h = ½ × 9.8 × 2.5²
h = 4.9 × 6.25
h = 30.625 ≈ 30.63 m
Therefore, the maximum height reached by the cannon ball is 30.63 m
Sorry!
This cannot be answered. We don't have weight, height, etc.
The formula we can use here is:
g = G m / r^2
where g is gravity, G is gravitational constant, m is
mass, and r is radius
Since G is constant, therefore we can equate two
situations:
g1 m1 / r1^2 = g2 m2 / r2^2
(10 m/s^2) r1^2 / m1 = g2 * (1/2 r1)^2 / (1/8 m1)
<span>g2 = 5 m/s^2</span>
