My Very Excellent Mother Just Served Us Nachos
(or Nine pickles if Pluto was a planet)
Mercury
Venus
Earth
Mars
Jupiter
Saturn
Uranus
Neptune
(Pluto)
hope that helped
Answer:
whatttttttttttt
Explanation:
the ಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠ
Kepler's third law states that, for a planet orbiting around the Sun, the ratio between the cube of the radius of the orbit and the square of the orbital period is a constant:

(1)
where
r is the radius of the orbit
T is the period
G is the gravitational constant
M is the mass of the Sun
Let's convert the radius of the orbit (the distance between the Sun and Neptune) from AU to meters. We know that 1 AU corresponds to 150 million km, so

so the radius of the orbit is

And if we re-arrange the equation (1), we can find the orbital period of Neptune:

We can convert this value into years, to have a more meaningful number. To do that we must divide by 60 (number of seconds in 1 minute) by 60 (number of minutes in 1 hour) by 24 (number of hours in 1 day) by 365 (number of days in 1 year), and we get
Answer:
a)
n=sin i/sin r
n= -0.305/-0.428
n=0.713
b)
sin c=1/n
sin c=1/0.713
sin c= 1.403
c=sin⁻¹(1.403)
c= 40.842°
Explanation:
i hope it will be helpful
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