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lisov135 [29]
3 years ago
10

Which situations will NOT increase the reactions rate of most chemical reactions?

Physics
2 answers:
kap26 [50]3 years ago
5 0
I think B I’m guessing
never [62]3 years ago
3 0

Answer:

D

Explanation:

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A student notices that an inflated balloon gets larger when it is warmed by a lamp. Which best describes the mass of the balloon
nirvana33 [79]
It gets larger because
well let me give you an example
so today in class we looked at a lava lamp with wax inside and there was a lightbulb at the bottom.
we watched as the wax floated up because the molecules inside the wax spreads out and makes the wax less dense.
the wax floats up because (which is related to the balloon getting bigger) the wax is getting less dense and the particles get bigger which ALSO makes the wax less dense.
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7 0
3 years ago
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Which quantity is measured in newton seconds (Ns)?
pshichka [43]

Answer:

Impulse

Explanation:

Impulse is force times time

7 0
2 years ago
When does a scientist create the conclusion?
Lerok [7]
After they have gathered enough information by testing the theory.
7 0
2 years ago
Does the Earth stay in one place throughout the year? If it doesn't, describe its motion and where it's located in the solar syt
stiv31 [10]

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6 0
3 years ago
A real object is 10.0 cm to the left of a thin, diverging lens having a focal length of magnitude 16.0 cm. What is the location
amm1812

Answer:

A)6.15 cm to the left of the lens

Explanation:

We can solve the problem by using the lens equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

q is the distance of the image from the lens

f is the focal length

p is the distance of the object from the lens

In this problem, we have

f=-16.0 cm (the focal length is negative for a diverging lens)

p=10.0 cm is the distance of the object from the lens

Solvign the equation for q, we find

\frac{1}{q}=\frac{1}{-16.0 cm}-\frac{1}{10.0 cm}=-0.163 cm^{-1}

q=\frac{1}{-0.163 cm^{-1}}=-6.15 cm

And the sign (negative) means the image is on the left of the lens, because it is a virtual image, so the correct answer is

A)6.15 cm to the left of the lens

6 0
3 years ago
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