Answer:
0.1 L
Explanation:
divide the volume value by 1000
The calculation for such a question can be achieved via Avogadro hypothesis
We know molar mass of CO2 is 44g/mole which is the sum of atomic masses i.e; C and 2 oxygen atoms
Molar mass of CO2 =12(C)+2*16(O) = 44 g/mole will contain 6.023 ※10^23 CO2 molecules ..
44g/mole = 6.023 ※10^23 CO2 molecules
=> 1g = (6.023/44) ※10^23 CO2 molecules
==> 8.80g = 8.80(6.023÷44)10^23 = 1.2046 ※10^23 molecules of CO2….
Thus there r 1.2046 ※10^23 molecules of CO2 in 8.80g
if u need to calculate no. of carbon atoms then multiply result by 1 and if u need no of oxygen atoms in 8.80g of co2 then multiply the result by 2 ….
francium , in the Periodic table the atomic radius increases from top to bottom in a group, and decreases from left to right across a period. making helium is the smallest element, and francium the largest.
Isotopes of any given factor all incorporate the equal variety of protons, so they have the identical atomic wide variety (for example, the atomic wide variety of helium is usually 2). Isotopes of a given factor include exceptional numbers of neutrons, therefore, special isotopes have special mass numbers.
Because some machine might not work and would give you the wrong answer