The prop prefix indicates that in the molecule, we have an arrangement of 3 carbon atoms.
<h3>What is a prefix in organic chemistry?</h3>
In the naming of organic compounds, we often use a prefix, a number to indicate the position of the substituents and a suffix.
The prop- prefix indicates that in the molecule, we have an arrangement of 3 carbon atoms.
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A 2% saltwater is a dilute solution in which the solvent is water and the solute is salt. The solvent is the component of the solution which comprise a large percentage while the solute comprise the smaller part. When alcohol is added, the solute still is salt and the solvent is the mixture of water and alcohol.
Because it requires more energy to create a neutron from a proton than it does to create a proton from a neutron, protons were formed more frequently than neutrons in the early universe. The correct answer is option b.
To find the answer, we need to know more about the early universe.
<h3>How the formation of proton over neutrons was favored in the early universe?</h3>
- A neutron is produced with greater energy than a proton.
- However, later on, some of the protons were changed into neutrons.
- Contrary to some claims, the proton is a stable particle that never decays, but the neutron is unstable outside of the nucleus and decays with a half life of around 10.5 minutes.
- However, very few would have had time to decay on the timeline you mention in your question.
- Every matter particle should have been accompanied by an antimatter particle, and every proton, neutron, and electron, by an anti-neutron and a positron, respectively.
- Where did all the antimatter go is the great mystery. There have been a few attempts to explain this, but they have failed.
Thus, we can conclude that, the correct answer is option b.
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The concentrations : 0.15 M
pH=11.21
<h3>Further explanation</h3>
The ionization of ammonia in water :
NH₃+H₂O⇒NH₄OH
NH₃+H₂O⇒NH₄⁺ + OH⁻
The concentrations of all species present in the solution = 0.15 M
Kb=1.8 x 10⁻⁵
M=0.15
![\tt [OH^-]=\sqrt{Kb.M}\\\\(OH^-]=\sqrt{1.8\times 10^{-5}\times 0.15}\\\\(OH^-]=\sqrt{2.7\times 10^{-6}}=1.64\times 10^{-3}](https://tex.z-dn.net/?f=%5Ctt%20%5BOH%5E-%5D%3D%5Csqrt%7BKb.M%7D%5C%5C%5C%5C%28OH%5E-%5D%3D%5Csqrt%7B1.8%5Ctimes%2010%5E%7B-5%7D%5Ctimes%200.15%7D%5C%5C%5C%5C%28OH%5E-%5D%3D%5Csqrt%7B2.7%5Ctimes%2010%5E%7B-6%7D%7D%3D1.64%5Ctimes%2010%5E%7B-3%7D)
![\tt pOH=-log[OH^-]\\\\pOH=3-log~1.64=2.79\\\\pH=14-2.79=11.21](https://tex.z-dn.net/?f=%5Ctt%20pOH%3D-log%5BOH%5E-%5D%5C%5C%5C%5CpOH%3D3-log~1.64%3D2.79%5C%5C%5C%5CpH%3D14-2.79%3D11.21)
