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nirvana33 [79]
3 years ago
12

Explain why we did not see distinct lines (like on an emission spectrum) when the metal salts were burned.

Chemistry
1 answer:
marysya [2.9K]3 years ago
6 0

Actually when we burn metal salts, we cannot actually really see distinct lines to appear because in reality, they are not really visible to the human eye. There is only a certain range of wavelength of light that our eyes can see.

To state in other way, some metal salts will give off light which has wavelengths that are outside of the visible region of the electromagnetic spectrum.<span> </span>

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When 2.3 × 10^3 g of CaCO3 are heated, the actual yield of CaO is 1.09 × 10^3g. What is
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The percent yield : 4. 84.58%

<h3>Further explanation</h3>

Reaction

CaCO₃ ⇄ CaO+CO₂

mass CaCO₃ = 2.3 × 10³ g

mol CaCO₃ (MW=100.0869 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{2.3\times 10^3}{100,0869}\\\\mol=22.98

From the equation, mol CaCO₃ : CaO = 1 : 1, so mol CaO=22.98

mass CaO(MW=56.0774 g/mol)⇒ (theoretical) :

\tt mass=mol\times MW\\\\mass=22.98\times 56,0774\\\\mass=1288.659~g

The percent yield :

\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{1090}{1288.659}\times 100\%\\\\\5yield=84.58\%

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3 years ago
Nancy and Hiyang are training for a race. They entered some of their training notes in a chart. Which information should be adde
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3 years ago
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Please answer asp! Which term is defined as the phase change from gas to liquid?
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3 years ago
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The total number of oxygen atoms indicated by formula Cu3(PO4)2?
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4 years ago
If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
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Answer:

The value of  the heat capacity of the Calorimeter  C_c = 54.4 \frac{J}{c}

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Given data

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From the given condition

Q = m_w C_w ΔT + C_c ΔT

Put all the values in above equation we get

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