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Karolina [17]
2 years ago
8

Imagine you are an astronaut and you travel to a planet with a much larger mass than Earth. How would this affect your weight? E

xplain your answer. (4 points)
Chemistry
1 answer:
Svetllana [295]2 years ago
3 0

Answer:

Explanation:

It may not make any difference. The information missing is the radius of the planet.

However for the purposes of the question, let us assume that it is roughly the same diameter of the earth. Then the weight of anyone would increase if the mass is all that changes..

The formula governing your weight is F = G * m1 *m2 / r^2. If m1 is the mass of the planet and it increases a lot then m2 (you) should increase.  The question is done by a proportion.

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A 4.86-gram sample of calcium reacted completely with oxygen to form 6.80 grams of calcium oxide. This reaction is represented b
sesenic [268]
The number of mole of Ca reacted is:
4.86 g Ca/ (40.08 g/mol Ca)= 0.121 mol Ca

Because Ca reacted completely with oxygen and there is 2 mol Ca, there is 1 mol O2 reacted.

Total mass of oxygen that reacted is:
0.121 mol Ca* (1mol O2/ 2 mol Ca)* (32 g O2/ 1 mol O2)= 1.94 g O2 reacted.

Hope this would help~
8 0
3 years ago
What is volume if the diameter of a sphere is 14cm<br>​
lisov135 [29]
Volume = (4/3) × π × r^3
R = 1/2 D
R = 7

V = 4/3 x π x 7^3

Exact Form:
1372 π/ 3

Decimal Form:
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6 0
2 years ago
Radio waves travel at the speed of light which is 3.00 x 10^8. How many minutes does it take for a radio message to reach saturn
ryzh [129]

Answer:

43.89 min

Explanation:

Given that:-

The speed of light = 3.00\times 10^8\ m/s

The distance = 7.9\times 10^8\ km

The conversion of distance in km to distance into m is shown below as:-

1 km = 1000 m

So,

Distance = 7.9\times 10^8\times 1000\ m=7.9\times 10^{11}\ m

The relation between speed distance and time is shown below as:-

Speed=\frac{Distance}{Time}

Thus,

3.00\times 10^8=\frac{7.9\times 10^{11}}{Time}

300000000\times time=10^{11}\times \:7.9\ s

Time = 2633.33 seconds

Also, 1 s = 1/60 min

So,

Time=\frac{2633.33}{60}\ min=43.89\ min

3 0
3 years ago
. In which reaction is nitric acid acting as an oxidising agent?
Talja [164]

Answer:

B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2

Explanation:

Hello,

In this case, we should understand oxidizing agents as those substances able to increase the oxidation state of another substance, therefore, in B. reaction we notice that copper oxidation state at the beginning is zero (no bonds are formed) and once it reacts with nitric acid, its oxidation states raises to +2 in copper (II) nitrate, thus, in B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 nitritc acid is acting as the oxidizing agent.

Moreover, in the other reactions, copper (A.), sodium (C. and D.) remain with the same initial oxidation state, +2 and +1 respectively.

Regards.

8 0
2 years ago
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What is the formula to find the area of circle​
Advocard [28]

Answer:

A= π * r *2

Explanation:

6 0
3 years ago
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