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fenix001 [56]
3 years ago
5

While at the country fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephants ears, you find

the motion somewhat unpleasant. To take your mind off your stomach, you wonder about the motion of the ride. You estimate the radius of the big wheel to be 15 cm, and you use your watch to find that each loop around takes 25 s.
a. What are your speed and magnitude of your acceleration?
b. What is the ratio of your apparent weight to your true weight at the top of the ride?
c. What is the ratio of your apparent weight to your true weight at the bottom?
Physics
1 answer:
marin [14]3 years ago
8 0

Answer:

0.038 m/s, 0.0096 m/s²

0.101

0.103

Explanation:

The speed is given by

v = 2πr / T

v = (2 * π * 0.15) / 25

v = 0.9426 / 25

v = 0.038 m/s

Acceleration, a is given by

a = v² / r =

a = 0.038² / 0.15

a = 0.001444 / 0.15

a = 0.0096 m/s²

Ratio of apparent weight to true weight at the top

w = m (g - a) / (m g)

w = 1 - a/g

w = 1 - 0.0096 / 9.81

w = 0.9904 / 9.81

w = 0.101

Ratio of apparent weight to true weight at bottom

w = m (g+a)/ (m g)

w = 1 + a/g

w = 1 + 0.0096 / 9.81

w = 1.0096 / 9.81

w = 0.103

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3 years ago
While driving a 2150 kg car, carl steps on the gas pedal, accelerating at 4.0 m/s2. If the coefficient of friction between his c
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Answer:

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Explanation:

To solve this problem we will use newton's second law, which tells us that the sum of forces is equal to the product of mass by acceleration.

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where:

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