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Gelneren [198K]
2 years ago
5

An object of mass 10 kg is moving along positive x- axis with velocity 5 m/s. At some point it breaks into two parts of 6 kg and

4 kg. 6 kg moves making 600 with x –axis and 4 kg moves making -300 with axis. What is velocity of their centre of mass after breaking?
Physics
1 answer:
vichka [17]2 years ago
6 0

Explanation:

Correct option is

B

−3m/s

2

Given,

m=10kg

u=10m/s

v=−2m/s

t=4sec

The acceleration is rate of change of velocity,

a=

t

v−u

a=

4

−2−10

a=

4

−12

=−3m/s

2

The correct option is B.

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Suppose that you measure the light of a star between 640 and 680 nm and you get a very strong peak around 650 nm. what can you s
Llana [10]

Answer: The star is moving away from Earth

Explanation:

Let's begin by explaining what the Doppler shift is:

This is related to the Doppler effect and refers to the change in a wave perceived frequency (or wavelength=color) when the emitter of the waves, and the observer move relative to each other.  

From there, it is deduced that the farther the object is, the more redshifted it is in its spectrum. For example, as a star moves away from the Earth, its espectrum turns towards the <u>red</u> and as the star moves toward the Earth, its espectrum turns towards the <u>blue</u>.

In this sense, since the peak in wavelength is around 650 nm, which corresponds to red, it can be said the star is moving away from Earth.

3 0
4 years ago
What is a mixture of rock and mineral fragments, organic matter, air, and water called?
Gekata [30.6K]
The answer should be soil
7 0
4 years ago
A painter sits on a scaffold that is connected to a rope passing over a pulley. The other end of the rope rests in the hands of
Doss [256]

Solution :

a). From Newtons second law,

F = ma

The total tension force is 2T.

∴ 2T - (m + M)g = (m+ M)a

Then

$a=\frac{2T-(m+M)g}{m+M}$

$a=\frac{2\times 600-(52+63)9.8}{52+63}$

   $=0.63 \ m/s^2$

b). From the person,

   F = ma

 T - Mg + N = Ma

or N = Ma + Mg - T

        = (63 x 9.8) + (52 x 9.8) - 600

        = 617.4 + 509.6 - 600

        = 527 N

6 0
3 years ago
For a point charge, how does the potential vary with distance from the point charge, r?
mr_godi [17]

For a point charge, how does the potential vary with distance from the point charge, r?

a constant

b. r.

c. 1/r.

d. 1/r^2.

e. r^2.

Answer:

The  correct option is  C

Explanation:

Generally for a point charge the electric potential is mathematically represented as

    V  =  \frac{k  Q  }{r }

Here we can deduce that the electric potential varies inversely with the distance i.e

      V  \  \alpha \  \frac{1}{r}

So

   

3 0
3 years ago
A high fountain of water is located at the center of a circular pool. Not wishing to get his feet wet, a student walks around th
Alisiya [41]

Answer:

The fountain is 3.43 m high.

Explanation:

Circumference of the pool = 15 m.

C = 2\pir

where C is the circumference and r its radius.

r = \frac{C}{2\pi }

 = \frac{15}{2(\frac{22}{7}) }

r = 2.3864

radius of the pool = 2.40 m

So that the height of the fountain, h, can be determined by applying trigonometric function.

Tan θ = \frac{opposite}{adjacent}

Tan 55 = \frac{h}{2.4}

h = Tan 55 x 2.4

  = 1.4282 x 2.4

  = 3.4277

h = 3.43 m

The height of the fountain is 3.43 m.

8 0
3 years ago
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