Answer:
A. Part a is the attachment
B. total work = 10.4kj
Explanation:

T1 = constant temperature
nRT1 = PaVa = PbVb
We write equation as

5ma = Pa, 5L = Va, Vb = 10L(temperature is doubled)

W1 = 25 ln2
W1 = 25 x 0.693
= 17.327kj
The isochoric expansion has no change in volume. So,
W2 = 0
Isothermal compression

T3 = constant temperature
nRT3 = PcVc = PdVd

Pc = 1mpa Vc = 10L Vd = 5L

= 10x-0.693
= -6.93kj
Isochoric compression has no change in volume. Workdone w4 = 0
Total workdone = w1 + w2 + w3 + w4
= 17.33 + 0 + (-6.93) + 0
= 10.4kj
Answer:
W= 638.1 J
Explanation:
As we know that
Work done is the area of the force and displacement diagram.
W=∫F.dx
W=Work
F=force
dx=Elemental displacement
From the diagram ,area A
A= 60 x 7.09 + 1/2 x 60 x 7.09
A= 638.1 J
So the work W
W= 638.1 J
Yes, because gravity will pull objects down to Earth.
<span>The forces of nature are phase forces.</span>
Answer:
Power= 0.5hp = 375W
T = 3hrs = 10800s
Power = Work done/ Time
Work = Power * Time = 375 * 10800 = 4050000J