Basically, the "push back" of the air against the object moving forward. It acts similar to friction, except the resistance is based on the shape of the object instead of the interaction of the object and the ground
The true velocity is 250 km/h.
Explanation:
As the aircraft is moving with speed of 300 km/h and the wind velocity is in east direction with the magnitude of 60 km/h. The resultant velocity or the true velocity can be found by the vector addition of the velocities.
If the true velocity is represented as V and the velocity of aircraft is represented as vₐ and the velocity of wind as vₓ, then
V² = vₐ² + vₓ² - vₐ.vₓ cosθ
So, the angle formed between them is 30°
Then, V² = (300)² + (60)² - 2×(300×60) cos 30°
V²=90000+3600-31177=62423
V =250 km/h
So, the true velocity is having magnitude of 250 km/h.
Thus, the true velocity is 250 km/h.
B because the ramp has the most mobility
Answer:
T = 0.00889 N*m
Explanation:
Given the initial speed
Vo = 9.0rev/s.
V = 65 rev/10s
V = 6.5 rev/s.
V = Vo + a*t
Solve to acceleration knowing the initial velocity and the velocity at 10 s
6.5 rev/s - 9 rev/s = a*10s
a = -0.25 rev/s^2.
Now the solve the time at stop time so V=0
V = Vo + a*t
0 = 9.0 - 0.25 rev/s *t,
t = 36 s The Stopping time.
36s - 10s = 26s
The torque can be find using the acceleration using the equation
T = I*a
I = 1/2*m*r^2
I = 1/2*0.725kg*(0.315m)^2= 0.0359kg*m^2
T = 0.0359kg*m^2*-0.25rev/s^2
T = 0.00889 N*m