Answer: 6 in.
Step-by-step explanation:
Hope this helped! :)
Answer:
![y=x^2+5x+20\\ \\ y=8x^2+35](https://tex.z-dn.net/?f=y%3Dx%5E2%2B5x%2B20%5C%5C%20%5C%5C%20y%3D8x%5E2%2B35)
Explanation:
The <em>end behavior</em> of a <em>rational function</em> is the limit of the function as x approaches negative infinity and infinity.
Note that the the values of even functions are the same for ± x. That implies that their limits for ± ∞ are equal.
The limits of the quadratic function of general form
as x approaches negative infinity or infinity, when
is positive, are infinity.
That is because as the absolute value of x gets bigger y becomes bigger too.
In mathematical symbols, that is:
![\lim_{x \to -\infty}3x^2=\infty\\ \\ \lim_{x \to \infty}3x^2=\infty](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%20-%5Cinfty%7D3x%5E2%3D%5Cinfty%5C%5C%20%5C%5C%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D3x%5E2%3D%5Cinfty)
Hence, the graphs of any quadratic function with positive coefficient of the quadratic term will have the same end behavior as the graph of y = 3x².
Two examples are:
![y=x^2+5x+20\\ \\ y=8x^2+35](https://tex.z-dn.net/?f=y%3Dx%5E2%2B5x%2B20%5C%5C%20%5C%5C%20y%3D8x%5E2%2B35)
Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
Answer:
8 out of 11
Step-by-step explanation: