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3 years ago

HELP please, will give brainliest

Mathematics

2 answers:

mario62 [17]3 years ago

6 0

You have the answer selected bro lol.

Flauer [41]3 years ago

4 0

<h3>The diagonal of square is 12√2 cm . So option C is your answer .</h3>

As we know that

Diagonal of square = √2 ( side of square )

So , we need to find side of square first

Using area of square = Side²

➩ 144 = S²

➩ S = √144

➩ Side = 12 cm

Now ,

➨ Diagonal = √2 ( 12 )

➨ Diagonal of square = 12√2

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Rounded to three decimal places, what is the value of r for this data set?

victus00 [196]

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3 years ago

If a triangle is 12 inches high and has a 20 inch long hypotenuse then how wide is it?

Ber [7]

Answer:

The triangle should be 16 inches wide.

Step-by-step explanation:

$\text {Use the Pythagorean Theorem to solve for the leg.}\\a^2 + b^2 =c^2$

What we know:

One of the legs measures 12 inches.

The hypotenuse is 20 inches.

We need to solve for b. Solving for a while b is 12 would also be acceptable.

$12^2 + b^2 = 20^2 \text { OR } a^2 +12^2=20^2$

We will use the first equation.

$12^2 + b^2 = 20^2\\12 * 12 = 144\\20 * 20 = 400\\\\\boxed {144 + b^2 = 400}$

$\text {Subtraction property of equality: }\\144-144+ b^2 = 400-144\\\boxed {b^2 = 256}\\\\\text {Take the square root of 256: }\\\sqrt{256}=\sqrt{b^2} \boxed {16 = b}$

The triangle should be 16 inches wide.

3 0

3 years ago

Factor the following: 1. 5(a+3)²- (a+3 2. p²- 6 - q · (p²- 6)²

scoundrel [369]

Answer:

1. $(a + 3)(5a-14)$

2. $(p^2-6)[1-q(p^2-6)]$

Step-by-step explanation:

1. The first thing to do to factor the expression is to take the expression (a + 3) as a common factor with its lowest exponent.

Then the expression. $5(a + 3)^2- (a + 3)$ remains as:

$(a + 3)(5 (a + 3) -1)\\\\(a + 3)(5a +15 -1)\\\\(a + 3)(5a-14)$

2. The first thing to do to factor the expression is to take the expression $p^2 -6$ as its common factor with its lowest exponent.

Then the expression $p^2- 6 - q(p^2- 6)^2$ remains as:

$(p^2-6)[1-q (p^2-6)]$

8 0

3 years ago

HELP please, will give brainliest​

HELP please, will give brainliest