Differentiate the function Y=(8x^4-x+1)(-x^5+5)

1 answer:

5 0

First, multiply the brackets out:

(8x^4 - x + 1)(-x^5 + 5)
= -8x^9 + x^6 - x^5 + 40x^4 - 5x + 5

Then, find f'(x) by multiplying each term by the power, then reducing the power by one:

f'(x) = -72x^8 + 6x^5 - 5x^4 + 160x^3 - 5

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I need help on question 8 ....

Romashka-Z-Leto [24]

Answer:

8a - 6b

You have to substitute in you other numbers:

a = 4 and b = 3

Your new equation would be:

8(4) - 6(3)

Now solve:

8 x 4 = 32

6 x 3 = 18

New problem:

32 - 18

= 14

So your answer is 14.

Step-by-step explanation:

Hope this helps!

From your neighborhood softie :)

7 0

2 years ago

What is the domain of F(x) = In(x)?

jekas [21]

Answer as an inequality: $x > 0$

Answer in interval notation: $(0, \infty)$

Answer in words: Set of positive real numbers

All three represent the same idea, but in different forms.

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Explanation:

Any log is the inverse of an exponential equation. Consider a general base b such that f(x) = b^x. The inverse of this is $f^{-1}(x) = \log_b(x)$

For the exponential b^x, we cannot have b^x = 0. We can get closer to it, but we can't actually get there. The horizontal asymptote is y = 0.

Because of this, $\log_b(x)$ has a vertical asymptote x = 0 (recall that x and y swap, so the asymptotes swap as well). This means we can get closer and closer to x = 0 from the positive side, but never reach x = 0 itself.

The domain of $\log_b(x)$ is x > 0 which in interval notation would be $(0, \infty)$ . This is the interval from 0 to infinity, excluding both endpoints.

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The natural log function Ln(x) is a special type of log function where the base is b = e = 2.718 approximately.

So,

$\log_e(x) = \text{Ln}(x)$