3 years ago

Fill in the blanks to write an equation for the given prop relationship.

Mathematics

1 answer:

3241004551 [841]3 years ago

8 0

hold up I’ll answer in a moment

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Translate the image by (x+4, y - 6)

irinina [24]

A’ = (2, -2)
B’ = (4, -16)
C’ = (1, -1)

7 0

3 years ago

Find the perimeter of the given triangle

faltersainse [42]

ABC is similar to PQR

that means AC/PR is a constant = 12/ 6 = 2

AC= 2 PR

AB= 2PQ

BC= 2QR

Perimeter of ABC= AB+BC+ CA=

2PQ + 2 QR + 2PR= 2( PQ+ QR+ PR)

= 2( perimeter of triangle PQR )

Perimeter of ABC= 2( perimeter of PQR) = 2* 36 = 72

Answer : 72.

8 0

3 years ago

Triangle LMN has coordinates L (0, 0), M (0, -2), and N (2, 0). If ΔLMN ≅ ΔXYZ, what is the measure of XZ?

salantis [7]

Check the picture below.

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4 years ago

Uhh... help with numb er seven because brother can’t solve it

Akimi4 [234]

It’s a parabola which is y= x^2. We know this because it’s vertex hits the origin. There are 2 answers there for it so just pick one.

7 0

3 years ago

What is the decibel level of a dog barking with intensity 10−5 watts per square inch? Use a logarithmic model to solve.

Vsevolod [243]

Answer:

The sound intensity is about 101.9 dB

Step-by-step explanation:

Sound intensity is the amount of sound energy per unit area.

The intensity of the dog bark is 10⁻⁵ W/in². The intensity of sound in decibels is given by:

$\beta=10\ dB*log(\frac{I}{I_o} )\\\\Where\ I=Sound\ intensity\ in \ W/m^2, I_o=reference\ sound\ intensity=10^{-12}\ W/m^2\, \beta= sound\ intensity\ in\ dB$

I = 10⁻⁵ W/in² = 0.0155 W/m²

Therefore:

$\beta=10\ dB*log(\frac{I}{I_o} )\\\\\beta=10\ dB*log(\frac{0.0155}{10^{-12}} )\\\\\beta=101.9\ dB$

The sound intensity is about 101.9 dB

5 0

3 years ago