Compare the 8's in the number 9,000,768.183

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

6 0

Answer:

One 8 is in the hundrenths place and another one in the ones place

Step-by-step explanation:

matrenka [14]3 years ago

3 0

The 8 in the ones place (on the left) is greater that the 8 in the hundredths place. (on the right)

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V=pi r^2 h solve for pi please help asap will mark brainliest

kogti [31]

Answer:

$\pi=\frac{v}{hr^2}$

Step-by-step explanation:

So we have:

$v=\pi r^2h$

And we want to solve for π.

First, divide both sides by h:

$\frac{v}{h}=\pi r^2$

Now, divide both sides again by r²:

$\pi=\frac{v}{hr^2}$

And this is our answer :)

7 0

3 years ago

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Can someone please explain - Thanks!

Reil [10]

They're not congruent.

If you count the numbers between AC and BE, they're different.

AC - goes from -7 to 0, which is 7 spaces
BE - goes from -2 to 6, which is 8 spaces

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4 years ago

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A tank that is 40% full contains 648 gallons of water. Use a double number line to find the maximum capacity of the water tank.

natali 33 [55]

We know that
Double number lines are best used to visualize equivalent ratios and describe a ratio relationship between two quantities.

start with the par 40% - 648 gal and let's calculate the other missing data
to find 10%-------> multiply 648 gal by (1/4)
to find 20%-------> multiply 648 gal by (1/2)
to find 30%-------> multiply 648 gal by (3/4)
to find 50%-------> multiply 648 gal by (5/4)
to find 60%-------> multiply 648 gal by (6/4)
to find 70%-------> multiply 648 gal by (7/4)
to find 80%-------> multiply 648 gal by (8/4)
to find 90%-------> multiply 648 gal by (9/4)
to find 100%-------> multiply 648 gal by (10/4)

Here is what the numbers would look like on a number line. They are lined up.
10% 20% 30% 40% 50% 60% 70% 80% 90% 100%
162 324 486 648 810 972 1134 1296 1458 1620

the answer is
the maximum capacity is 1620 gallons of water.

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3 years ago

Each side of a square is increasing at a rate of 8 cm/s. At what rate (in cm2/s) is the area of the square increasing when the a

statuscvo [17]

Answer:

Step-by-step explanation:

This is nice and simple. I'm going to walk through it like I do when teaching this concept to my class for the first time. This is a good problem for that.

We are given a square and we are looking for the rate at which the area is increasing when a certain set of specifics are given. That means that the main equation for this problem is the area of a square, which is:

$A=s^2$ where s is a side.

Since we are looking for the rate at which the area is changing, $\frac{dA}{dt}$ , we need to take the derivative of area formula implicitly:

$\frac{dA}{dt}=2s\frac{ds}{dt}$ that means that if $\frac{dA}{dt}$ is our unknown, we need values for everything else. We are given that the initial area for the square is 49. That will help us determine what the "s" in our derivative is. We plug in 49 for A and solve: