The 600-N ball shown is suspended on a string AB and rests against the frictionless vertical wall. The string makes an angle of

Question

3 years ago

6

The 600-N ball shown is suspended on a string AB and rests against the frictionless vertical wall. The string makes an angle of

30° with the wall. The line AB goes through the center of the ball, and the contact point with the wall is at the same vertical height as the center of the ball. The ball presses against the wall with a force of magnitude:

Physics

1 answer:

Harrizon [31] · Answer 1 · 2022-03-02T05:44:21+03:00

Harrizon [31]3 years ago

4 0

Answer: T = 692.82 and 346.4 N

Explanation:

Given that;

w = 600 N

∅ = 30°

ΣFy = ma

a = 0 m/s²

ΣF = T(cos30°) - W = 0

T(cos30°) = W

we Divide both sides by cos30°

T = W / cos30o

T= 600N / cos30°

T = 692.82

and ∑fx

F = T sin∅

F = 692.82 × (sin30°)

F = 346.4 N