The 600-N ball shown is suspended on a string AB and rests against the frictionless vertical wall. The string makes an angle of
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There are 4 hydrogens on the right side , and 2 hydrogens on the left per molecule of
. To get the same number of hydrogens on both sides, the coefficient should be 2.
(Then the number of oxygens will be consistent, since contributes 2 oxygens, and so does
.)
Answer:
HERE'S MY UNDERSTANDING OF THE DIFFERENCE
