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dimaraw [331]
3 years ago
11

Sandra joined a new company in HR. She believes most of the employees are overburdened and stressed. What action should she unde

rtake to help them reduce their stress levels? recruit new staff of people who can handle the pressure well arrange for a time management training arrange family excursions at regular intervals chalk out a policy that would pay them for their extra work hours
Physics
2 answers:
____ [38]3 years ago
5 0

Answer:

The correct answer is option B, Arrange for a time management training

Explanation:

Most of the staff is overburdened which implies that amount of work given to them is not timely managed. Thus, it would be beneficial to conduct a time management training where the employees can learn to priorities their work and divide it into modules so that they don’t stress out themselves. Time management will also make them understand the importance of doing the right task at right time so that it does not become tedious at later stage.

shtirl [24]3 years ago
4 0
Arrange for a time management training meeting
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At the outer edge of a rotating space habitat, 130 m from the center, the rotational acceleration is g. What is the rotational a
enyata [817]

Answer:

Explanation:

Given:

R1 = 130 m

R2 = 65 m

w^2R = g

Assume, g = 9.81 m/s^2

w^2 = 9.81/130

w = 0.275 rad/s

At R2 = 65 m

g = w^2R

= (0.275^2) × 65

= 4.905 m/s^2

In conclusion,

g × R = k

g1/R1 = g2/R2

g2 = (g1 × 65)/130

= g1 ×1/2

= g1/2

6 0
3 years ago
The four giant gas planets that are made primarily of lightweight elements are
Hoochie [10]
D) although recent research (1990's) has shown Uranus and Neptune to be ice giants and have heavier substances.
8 0
3 years ago
xConsider the following reduction potentials: Cu2+ + 2e– Cu E° = 0.339 V Pb2+ + 2e– Pb E° = –0.130 V For a galvanic cell employi
slega [8]

Answer:

Approximately \rm 90\; kJ.

Explanation:

Cathode is where reduction takes place and anode is where oxidation takes place. The potential of a electrochemical reaction (E^{\circ}(\text{cell})) is equal to

E^{\circ}(\text{cell}) = E^{\circ}(\text{cathode}) - E^{\circ}(\text{anode}).

There are two half-reactions in this question. \rm Cu^{2+} + 2\,e^{-} \rightleftharpoons Cu and \rm Pb^{2+} + 2\,e^{-} \rightleftharpoons Pb. Either could be the cathode (while the other acts as the anode.) However, for the reaction to be spontaneous, the value of E^{\circ}(\text{cell}) should be positive.

In this case, E^{\circ}(\text{cell}) is positive only if \rm Cu^{2+} + 2\,e^{-} \rightleftharpoons Cu is the reaction takes place at the cathode. The net reaction would be

\rm Cu^{2+} + Pb \to Cu + Pb^{2+}.

Its cell potential would be equal to 0.339 - (-0.130) = \rm 0.469\; V.

The maximum amount of electrical energy possible (under standard conditions) is equal to the free energy of this reaction:

\Delta G^{\circ} = n \cdot F \cdot E^{\circ} (\text{cell}),

where

  • n is the number moles of electrons transferred for each mole of the reaction. In this case the value of n is 2 as in the half-reactions.
  • F is Faraday's Constant (approximately 96485.33212\; \rm C \cdot mol^{-1}.)

\begin{aligned}\Delta G^{\circ} &= n \cdot F \cdot E^{\circ} (\text{cell})\cr &= 2\times 96485.33212 \times (0.339 - (-0.130)) \cr &\approx 9.0 \times 10^{4} \; \rm J \cr &= 90\; \rm kJ\end{aligned}.

5 0
2 years ago
A college student is working on her physics homework in her dorm room. Her room contains a total of 6.0 x 10^26 gas molecules. A
IceJOKER [234]

Answer:

Temperature, T = 3.62 kelvin

Explanation:

It is given that,

Total number of gas molecules, N=6\times 10^{26}

Her body is converting chemical energy into thermal energy at a rate of 125 W, P = 125 W

Time taken, t = 6 min = 360 s

Energy of a gas molecules is given by :

\Delta E =\dfrac{3}{2}NkT

T=\dfrac{2E}{3Nk}, k is Boltzmann constant

T=\dfrac{2\times P\times t}{3Nk}

T=\dfrac{2\times 125\times 360}{3\times 6\times 10^{26}\times 1.38\times 10^{-23}}

T = 3.62 K

So, the temperature increases by 3.62 kelvin. Hence, this is the required solution.

4 0
3 years ago
A free positive charge released in an electric field will:
choli [55]

Answer:

accelerate in the direction in which the electric field is pointing.

Explanation:

The positive charge feels a force in the same direction as the electric field

F=Eq  

F and E are vectors, q is a scalar

(if it were a negative charge the force would be in the opposite direction)

that force will produce an acceleration in the same direction, that acceleration will cause the particle to move in the same direction, ie the direction of the electric field.

7 0
3 years ago
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