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Zarrin [17]
3 years ago
7

If I travel 100 m N in 5 seconds, what is my average velocity?

Physics
2 answers:
sveta [45]3 years ago
5 0
You would divide the 100 m by 5 seconds which is 20 m average
Nina [5.8K]3 years ago
3 0

Answer:

Explanation:

Average- velocity = \frac{displacement }{time} \\A.V = \frac{100}{5} \\A.V = 20

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Hurricanes are least likely to form in which of the following?
Sholpan [36]
The best and most correct answer among the choices provided by the question is the second choice "Lake Michigan"


A hurricane<span> is a storm that occurs in the </span>Atlantic Ocean <span>and northeastern Pacific </span>Ocean<span>, a typhoon occurs in the northwestern Pacific </span>Ocean<span>, and a cyclone occurs in the south Pacific or Indian </span>Ocean<span>. Tropical cyclones can be categorized by intensity.</span>

I hope my answer has come to your help. God bless and have a nice day ahead!
3 0
3 years ago
Ms. Kasper is in a panic. Her cat, Penny, is stuck in a tree and about to jump out. In order to save her cat, Ms. Kasper needs t
Misha Larkins [42]

Answer:

Speed greater than 4 m/s

Explanation:

Given that Ms. Kasper is in a panic. Her cat, Penny, is stuck in a tree and about to jump out. In order to save her cat, Ms. Kasper needs to run to the tree, 12 meters away. If it takes her cat, 3 seconds to fall, how fast would Ms. Kasper have to run to save her cat?

The distance = 12 m

Time = 3s

Speed = distance/time

Speed = 12/3

Speed = 4 m/s

Ms Kasper must run at speed more than 4m/s for her to save the cat.

3 0
3 years ago
What happens when an atom gives up loosely held valence electrons to another atom​
vazorg [7]

Answer:

The number of valence electrons increases to 8 or, the atom gives up loosely held valence electrons.

Explanation:

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3 0
3 years ago
What's the energy transfer for a catapult
just olya [345]
Kinetic energy is the energy for a catapult.
3 0
3 years ago
A(n) 1400-kg car going at 6.32 m/s in the positive x direction collides with a 2900-kg truck at rest. The collision is totally i
tresset_1 [31]

Answer:

a) Acceleration of the car is given as

a_{car} = -21 m/s^2

b) Acceleration of the truck is given as

a_{truck} = 10.15 m/s^2

Explanation:

As we know that there is no external force in the direction of motion of truck and car

So here we can say that the momentum of the system before and after collision must be conserved

So here we will have

m_1v_1 + m_2v_2 = (m_1 + m_2)v

now we have

1400 (6.32) + 2900(0) = (1400 + 2900) v

v = 2.06 m/s

a) For acceleration of car we know that it is rate of change in velocity of car

so we have

a_{car} = \frac{v_f - v_i}{t}

a_{car} = \frac{2.06 - 6.32}{0.203}

a_{car} = -21 m/s^2

b) For acceleration of truck we will find the rate of change in velocity of the truck

so we have

a_{truck} = \frac{v_f - v_i}{t}

a_{truck} = \frac{2.06 - 0}{0.203}

a_{truck} = 10.15 m/s^2

5 0
3 years ago
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