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Liula [17]
3 years ago
14

A 2kg object is moving with speed 5ms. then hits a

Physics
1 answer:
densk [106]3 years ago
6 0

Given :

A 2kg object is moving with speed 5m/s. then hits a  wall in 0.5s before reversing its direction with a speed of 2m/s.

To Find :

The impulse.

Solution :

Impulse can be calculated by change in momentum :

I = mv_f - mv_i\\\\I = 2\times( -2 + 5 )\ kg \ m/s\\\\I = 6 \ kg \ m/s

Therefore, the impulse is 6 kg m/s.

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A robin is a small carnivore bird which feed on insects, earthworms, spiders and bees. It needs about 60 calories per day from these organisms. This bird has a short lifespan of only 7 years. Hope this answers the question. Have a nice day.
8 0
3 years ago
The force of kinetic friction between a box sliding on a surface depends on the ____ .
vazorg [7]

Answer: speed of the box

Explanation: maybe

6 0
2 years ago
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Why was the concern over global cooling replaced with a concern over global warming?
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4 0
3 years ago
A +0.2 µC charge is in an electric field. What happens if that charge is replaced by a +0.4 µC charge?
AleksandrR [38]

Explanation:

It is known that electric field is responsible for creating electric potential. As a result, it depends only on the electric field and not on the magnitude of charge.

So, when a charge is increased by a factor of 2 then electric potential will remain the same. Since, expression to calculate the electric potential is as follows.

                 U = qV

Since, the electric potential is directly proportional to the charge. Hence, when 0.2 \mu C tends to replaced by 0.4 \mu C then charge is increased by a factor of 2. Hence, the electric potential energy is doubled.

Thus, we can conclude that if that charge is replaced by a +0.4 µC charge then electric potential stays the same, but the electric potential energy doubles.

4 0
3 years ago
A jet accelerates from rest down a runway at 1.75m/s² for a distance of 1500 m before takeoff.
babunello [35]
A. Using the third equation of motion:
v2 = u2 + 2as
from the question;
the jet was initially at rest
hence u = 0
a = 1.75m/s2
s = 1500m
v2 = 02 + 2(1.75)(1500)
v2 = 5250
v = √5250
v = 72.46m/s
hence it moves with a velocity of 72.46m/s.
b. s = ut + 1/2at2
1500 = 0(t) + 1/2(1.75)t2
1500 × 2 = 2× 1/2(1.75)t2
3000 = 1.75t2
1714.29 = t2
41.4 = t
hence the time taken for the plane to down the runway is 41.4s.


Read more on Brainly.com - brainly.com/question/18743384#readmore
8 0
3 years ago
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