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3 years ago

A 2kg object is moving with speed 5ms. then hits a

Physics

1 answer:

densk [106]3 years ago

6 0

Given :

A 2kg object is moving with speed 5m/s. then hits a wall in 0.5s before reversing its direction with a speed of 2m/s.

To Find :

The impulse.

Solution :

Impulse can be calculated by change in momentum :

$I = mv_f - mv_i\\\\I = 2\times( -2 + 5 )\ kg \ m/s\\\\I = 6 \ kg \ m/s$

Therefore, the impulse is 6 kg m/s.

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You can increase the rate solute dissolves in solvent by______

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Crushing particles of solute. The more surface area of the solute exposed to the solvent the faster the solute will dissolve and react with the solvent

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4 years ago

Read 2 more answers

Suppose a soup can is made from a sheet of steel19 which is .13 mm thick. If the can is 11 cm high and 6 cm in diameter, use dif

Flura [38]

Answer:

The can mass is 0,00359 kg or 3,59 g

Explanation:

1. Relevant Data:

Steel thickness= 0.13 mm or 0.013 mm

h=11 cm

d=6 cm

ρ=800 kg/m^3

2. Calculate mass from densisty equation:

$\rho=\frac{m}{v}$ , then $m=\rho .v$

We need to estimate the volume of the can to calculate the mass.

3. Estimate volume using differentials:

Cylinder volume equation is:

$V=\frac{1}{4}\pi d^{2}h$

Considering that the can is an object with a hole inside, then we need to estimate the real volume of the sheet of steel.

Using differentials we have:

$dV=\frac{1}{2}\pi Dh (dD)$

Then, we could say that $dD=0.013 cm$

Replacing the values of d, h and dD, we obtain:

$dV=\frac{1}{6}\pi (6 cm)(11 cm)(0,013 cm)$

$dV=0,4492 cm^3$

4. Calculate the mass

Convert volume unit into $m^3$

$0,4492 cm^3x\frac{1 m^3}{1x10^6 cm^3} =0,4492 x 10^-6 m^3$

Calculate mass

$m=\rho .v$

$m=8000 \frac{kg}{m^3}.0,4492 x10^-6 m^3$

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4 years ago

a body starts from rest and moving under uniform acceleration of 4 metre per second square travel half of its total path during

lakkis [162]

Answer:

t = 3.414 s

s = 23.3 m

Explanation:

Let t be the total time of motion

Let s be the total distance of motion

s - s/2 = ½at² - ½a(t - 1²) = ½a(t² - (t - 1)²)

s/2 = ½a(t² - (t² - 2t + 1)) = ½a(t² - t² + 2t - 1)

s = a(2t - 1)

s = 4(2t - 1)

s = 8t - 4

8t - 4 = ½4t²

8t - 4 = 2t²

0 = 2t² - 8t + 4

0 = t² - 4t + 2

t = (4 ±√(4² - 4(1)(2))) / 2 = (4 ± √8)/2 = 2 ± √2

t = 3.414 s

t = 0.5857... s which we ignore because it does not have a full last second.

s = ½(4)3.414² = 23.3137... 23.3 m

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3 years ago

1. Identify the significance of the following terms to the subject of the Civil War.

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4 years ago

Refer to the image. Calculate the magnitude of change in velocity of the cue ball.

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Answer:

If you add the 2 velocity vectors you get the velocity of the third vector which is the (change in) velocity of the cue ball after striking the cushion

V * 2 * cos 45 = 4 * cos 45 = 2.83 m/s

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2 years ago