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3 years ago

A 2kg object is moving with speed 5ms. then hits a

Physics

1 answer:

densk [106]3 years ago

6 0

Given :

A 2kg object is moving with speed 5m/s. then hits a wall in 0.5s before reversing its direction with a speed of 2m/s.

To Find :

The impulse.

Solution :

Impulse can be calculated by change in momentum :

$I = mv_f - mv_i\\\\I = 2\times( -2 + 5 )\ kg \ m/s\\\\I = 6 \ kg \ m/s$

Therefore, the impulse is 6 kg m/s.

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Most problems addressed by the technological design process have only one solution true/false

ludmilkaskok [199]

XD I think its false

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3 years ago

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Which bird on the wire, the one with a mass of 50g or the one with a mass of 60g, has the most potential energy?

Fynjy0 [20]

Answer:

one with 60g have the more potential

Explanation:

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3 years ago

Jet aircraft maintenance crews are required to wear protective earplugs. Members of a particular crew wear earplugs that reduce

Taya2010 [7]

Answer:

So the sound intensity level they would experience without the earplugs is 110.32dB.

Explanation:

Given data

Sound intensity by factor =215

Sound intensity level =87 dB

To find

Sound intensity level they would experience without the earplugs

Solution

First we need to find the new sound intensity level

$I_{n}=215(10^{\frac{87}{10} } )\\I_{n}=1.08*10^{11})$

The dB can be calculated as:

$dB=10log(I_{n})\\$

Substitute the given values

$dB=10log(1.08*10^{11})\\dB=110.32dB$

So the sound intensity level they would experience without the earplugs is 110.32dB.

7 0

3 years ago

Would this one be correct?(C.)

BaLLatris [955]

No. The correct one would be D .

5 0

3 years ago

Two equal, but oppositely charged particles are attracted to each other electrically. The size of the force of attraction is 48.

galina1969 [7]

Given:

The force of attraction is F = 48.1 N

The separation between the charges is

$\begin{gathered} r=\text{ 60.9 cm} \\ =\text{ 60.9}\times10^{-2}\text{ m} \end{gathered}$

Also, the magnitude of charge q1 = q2 = q.

To find the magnitude of charge.

Explanation:

The magnitude of charge can be calculated by the formula

$\begin{gathered} F=\frac{k(2q)}{r^2} \\ q=\frac{Fr^2}{2k} \end{gathered}$

Here, k is the Coulomb's constant whose value is

$k\text{ = 9}\times10^9\text{ N m}^2\text{ /C}^2$

On substituting the values, the magnitude of charge will be

$\begin{gathered} q=\frac{48.1\times(60.9^\times10^{-2})^2}{2\times9\times10^{^9}} \\ =9.91\times10^{-10}\text{ C} \\ =9.91\times10^{-4}\text{ }\mu C \end{gathered}$

Thus, the magnitude of each charge is 9.91 x 10^(-4) micro Coulombs.

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1 year ago