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IgorLugansk [536]
3 years ago
7

Calculate the average velocity of a car that travels 555 km north east in 3.7 hours

Physics
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

Your answer:

150 kilometer's per hour.

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Give me fun facts, the most fun fact will get brainly Est (i like animals)
swat32

Answer:

here are some fun facts lol

Dolphins sleep with one eye open

Hot water will turn into ice faster than cold water.

A crocodile cannot stick its tongue out

It is physically impossible for pigs to look up into the sky

Grapes light on fire in the microwave

McDonald's once created bubblegum-flavored broccoli.

It's impossible to sneeze with your eyes open.

High Heels Were Originally Men's Shoes

The strongest muscle in the body is the tongue.

While they are hibernating, bears do not urinate

Gummy bears were originally called "dancing bears."

Explanation:

3 0
2 years ago
Read 2 more answers
If an object is placed at the center of carvature of a convance mirror the image formed is called
Natasha_Volkova [10]

Answer:

When the object is placed between centre of curvature and principal focus of a concave mirror the image formed is beyond C as shown in the figure and it is real, inverted and magnified.

3 0
2 years ago
a tire with inner volume of 0.0250m^3 is filled with air at a gauge pressure of 36.0 psi. If the tire valve is opened to the atm
enyata [817]

Answer: Escaped volume = 0.0612m^3

Explanation:

According to Boyle's law

P1V1 = P2V2

P1 = initial pressure in the tire = 36.0psi + 14.696psi = 50.696psi (guage + atmospheric pressure)

P2 = atmospheric pressure= 14.696psi

V1 = volume of tire =0.025m^3

V2 = escaped volume + V1 ( since air still remain in the tire)

V2 = P1V1/P2

V2 = 50.696×0.025/14.696

V2 = 0.0862m^3

Escaped volume = 0.0862 - 0.025 = 0.0612m^3

5 0
3 years ago
Acceleration increases over time once a force is applied to the object. Determine the acceleration at 3.5 sec? A) 3 m/s2 B) 6 m/
Novay_Z [31]

Answer: Acceleration does not increase over time once a force is applied to the object. It depends on the force and the object's mass. If those don't change, then the acceleration is constant.

Explanation:. F = M • a

We don't know either of those numbers, so we can't answer the question.

4 0
3 years ago
Read 2 more answers
A string of mass 60.0 g and length 2.0 m is fixed at both ends and with 500 N in tension. a. If a wave is sent along this string
Darya [45]

Answer:

a

The  speed of  wave is   v_1  = 129.1 \ m/s

b

The new speed of the two waves is v =  129.1 \ m/s

Explanation:

From the question we are told that

    The mass of the string is  m  =  60 \ g  =  60 *10^{-3} \ kg

    The length is  l  =  2.0 \ m

    The tension is  T  = 500 \ N

Now the velocity of the first wave is mathematically represented as

     v_1  = \sqrt{ \frac{T}{\mu} }

Where  \mu is the linear density which is mathematically represented as

      \mu  =  \frac{m}{l}

substituting values    

     \mu  =  \frac{ 60 *10^{-3}}{2.0 }

     \mu  =  0.03\ kg/m

So

   v_1  = \sqrt{ \frac{500}{0.03} }

   v_1  = 129.1 \ m/s

Now given that the Tension, mass and length are constant the velocity of the second wave will same as that of first wave (reference PHYS 1100 )

     

8 0
3 years ago
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