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3 years ago

Why does sound propagate faster in solid bodies than in liquids and faster in liquids than in air?

Physics

1 answer:

storchak [24]3 years ago

4 0

Answer:

see below

Explanation:

this is because particles in solids are packed very closely together, thus , the particles collide with each other frequently and thus transfer of energy is faster. however, particles in liquid are closely packed but not as close as in solid so the particles do not collide as frequently. thus, transfer of energy slower than in solid. furthermore, the particles in gas are spaced far apart from each other, thus the particles don't collide with each other frequently, thus transfer of energy is very slow in gas.

hope you get it,

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A pilot heads her jet due east. The jet has a speed of 425 mi/h relative to the air (in other words, if the air were still, the

Elza [17]

Answer:

The resultant velocity of the jet as a vector in component form 426.87 mi/hr 5.36 degrees North.

Explanation:

Vectors are quantities that have their magnitude and direction .

Sketching out the problem given, by using straight lines to represent each of the vectors, we will have a right angled triangle as shown below.

The solution can be obtained by applying Pythagoras theorem to

resolve the vectors.

Velocity of jet plane = 425 mi/hr

velocity of air = 40 mi/hr

Resultant of the vectors = $\sqrt[]{425^{2}+40^{2}}=426.87$ mi/hr

Vector direction = $tan^{-1}(\frac{40}{425})= 5.36 degrees$

hence the velocity is 426.87 mi/hr in a direction 5.36 degrees inclined Northward

5 0

3 years ago

A 2 kg toy cart and a 6 kg toy cart have a spring compressed between them. When the spring expands, it sends the 2 kg toy cart o

harkovskaia [24]

Answer:

The speed of second toy cart is 4 m/s.

Explanation:

Given that,

Mass of first toy cart = 2 kg

Mass of second toy cart = 6 kg

Speed of first toy cart = 12 m/s

We need to calculate the speed of second toy cart

Using formula of momentum

$m_{1}v_{1}=m_{2}v_{2}$

Where, m₁ = mass of first toy cart

m₂ = mass of second toy cart

v₁ = velocity of first toy cart

v₂ = velocity of second toy cart

Put the value into th formula

$2\times12=6\times v_{2}$

$v_{2}=\dfrac{2\times12}{6}$

$v_{2}=4\ m/s$

Hence, The speed of second toy cart is 4 m/s.

(c) is correct option

4 0

4 years ago

Melting Point of Substances

frez [133]

<span>(kg) Melting Point of Tin

</span>

5 0

3 years ago

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When a person is jump roping where do they have the most potential<br> energy?

Mazyrski [523]

Answer:

At the bottom when they hit the ground.

7 0

2 years ago

An object is placed a distance of twice the focal length away from a diverging lens. What is the magnification of the image?

Lesechka [4]

Answer:

+1/3

Explanation:

The lens equation states that:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

For a diverging lens, the focal length is negative: $f=-f$

and we also know that the object is placed a distance of twice the focal length, so $p=2f$

So we can find q from the equation above

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-f}-\frac{1}{2f}=-\frac{3}{2f}\\q=-\frac{2}{3}f$

And the magnification of the image is given by

$M=-\frac{q}{p}=-\frac{-\frac{2}{3}f}{2f}=\frac{1}{3}$

5 0

4 years ago

Read 2 more answers