Answer:
![S_a_v_e_r_a_g_e=48km/h](https://tex.z-dn.net/?f=S_a_v_e_r_a_g_e%3D48km%2Fh)
Explanation:
Ok, the average speed can be calculate with the next equation:
(1)
Basically the car cover the same distance "d" two times, but at different speeds, so:
![Total\hspace{3}distance=2*d](https://tex.z-dn.net/?f=Total%5Chspace%7B3%7Ddistance%3D2%2Ad)
and the total time would be the time t1 required to go from A to B plus the time t2 required to go back from B to A:
![Total\hspace{3}time=t1+t2](https://tex.z-dn.net/?f=Total%5Chspace%7B3%7Dtime%3Dt1%2Bt2)
From basic physics we know:
![t=\frac{d}{S1}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bd%7D%7BS1%7D)
so:
![t1=\frac{d}{S1}](https://tex.z-dn.net/?f=t1%3D%5Cfrac%7Bd%7D%7BS1%7D)
![t2=\frac{d}{S2}](https://tex.z-dn.net/?f=t2%3D%5Cfrac%7Bd%7D%7BS2%7D)
Using the previous information in equation (1)
![S_a_v_e_r_a_g_e=\frac{2*d}{\frac{d}{S1} +\frac{d}{S2} }=\frac{2*d}{\frac{d*S2+d*S1}{S1+S2} }](https://tex.z-dn.net/?f=S_a_v_e_r_a_g_e%3D%5Cfrac%7B2%2Ad%7D%7B%5Cfrac%7Bd%7D%7BS1%7D%20%2B%5Cfrac%7Bd%7D%7BS2%7D%20%7D%3D%5Cfrac%7B2%2Ad%7D%7B%5Cfrac%7Bd%2AS2%2Bd%2AS1%7D%7BS1%2BS2%7D%20%7D)
Factoring:
(2)
Finally, replacing the data in (2)
![S_a_v_e_r_a_g_e=\frac{2*40*60}{60+40} =48km/h](https://tex.z-dn.net/?f=S_a_v_e_r_a_g_e%3D%5Cfrac%7B2%2A40%2A60%7D%7B60%2B40%7D%20%3D48km%2Fh)
Answer:
not work.
Explanation:
if u are saying in a series circuit...
if 1 build burns out and theres other bulbs the circuit wont work anymore.
It’s the wavelength I believe
Answer:
Option B. Decreases
Explanation:
Coulomb's law states that:
F = Kq₁q₂ / r²
Where:
F => is the force of attraction between two charges
K => is the electrical constant.
q₁ and q₂ => are the two charges
r => is the distance apart.
From the formula:
F = Kq₁q₂ / r²
The force of attraction (F) is inversely proportional to the square of their separating distance (r).
This implies that as the distance between them increase, the force of attraction between the two charges will decrease and as the distance between two charges decrease, the force of attraction between them will increase.
Considering the question given above and the illustration given above, the force of attraction will decrease as their distance of separation increases.
Option B gives the right answer to the question.