Answer: 1.88 N
Explanation:
Data:
Force = 4.00N
angle = 62°
horizontal force = ?
Solution:
The trigonometric ratio that relates horizontal - leg to hypotenuse is the cosine.
That ratio is:
horizontal - leg
cos(angle) = -------------------------
hypotenuse
So, applied to the force, that is:
horizontal force
cos (angle) = -----------------------------------
total force
So, clearing the horizontal component you get:
horizontal force = force * cos (angle)
Substitute the data given:
horizontal force = 4.00N * cos(62°) = 4.00N * 0.4695 = 1.88 N
Answer: 1.88N
The Coulomb force between two charges is defined as: Fc=(k*Q₁*Q₂)/r² where k=9*10^9 N m² C⁻², Q₁ and Q₂ are charges and r is the distance between those charges.
In our case:
Q₁=2*10^-6 C
Q₂=4*10^-6 C
r=2 m
Now we simply plug in the numbers into the equation:
Fc={(9*10^9)*(2*10^-6)*(4*10^-6)}/2^2=0.018 N
The Coulombs force between the two positive charges is Fc=0.018 N and it is a repulsive force because both charges are positive.
