If a proton were released in the electric field above, what direction would it move?
1 answer:
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Answer:
(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East
(b) When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West
Explanation:
Given;
a force vector points due east, = 140 N
let the second force =
let the resultant of the two vectors = F
(a) When the resultant force is pointing along east line
the second force must be pointing due east
(b) When the resultant force is pointing along west line
the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.