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ella [17]
2 years ago
11

POTENTIAL I KINETIC ENERGY

Physics
1 answer:
TEA [102]2 years ago
4 0

7kinetic energy is decreasing in B

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2 equal charges, 27 micro Coulomb each, are separated by 5 cm. Find force between those.
padilas [110]

Answer:

The force between charges is  F= 2.624*10^3N.

Explanation:

The Coulomb force F between the two charges q_1 and q_2 separated by distance d is given by the equation

F = k\dfrac{q_1q_2}{d^2}

where k is the coulombs constant, and has the value

k= 9*10^9N\cdot C\cdot m^2.

Now in our case

q_1=q_2=27\mu C =27*10^{-6}C

and

d= 5cm =0.05m,

therefore, the Coulomb force between the charges is

F =( 9*10^9N\cdot C\cdot m^2)*\dfrac{(27*10^{-6}C)(27*10^{-6}C)}{(0.05m)^2}

\boxed{ F= 2.624*10^3N}

3 0
3 years ago
Which of the following statements about igneous rocks is correct?
g100num [7]
Although you have not provided the possible answers, igneous rocks are formed out of magma or lava, with or without crystals, and they can be found either on the surface or under it. This is a basic description of the type of rocks, so it might fit some of the answers you may have.
3 0
3 years ago
Estimate the number of photons emitted per second from 1.0 cm2 of a person's skin if a typical emitted photon has a wavelength o
Diano4ka-milaya [45]

Answer:

2.63 x 10^18

Explanation:

A = 1 cm^2 = 1 x 10^-4 m^2

λ = 10,000 nm = 10,000 x 10^-9 m = 10^-5 m

T = 37 degree C = 37 + 273 = 310 k

Energy of each photon = h c / λ

where, h is the Plank's constant and c be the velocity of light

Energy of each photon = (6.63 x 10^-34 x 3 x 10^8) / 10^-5 = 1.989 x 10^-20 J

Energy radiated per unit time = σ A T^4

Where, σ is Stefan's constant

Energy radiated per unit time = 5.67 x 10^-8 x 10^-4 x 310^4 = 0.05236 J

Number of photons per second = Energy radiated per unit time / Energy of  

                                                                                               each photon

Number of photons per second = 0.05236 / (1.989 x 10^-20) = 2.63 x 10^18

4 0
3 years ago
What do you mean by reflection of sound​
Bogdan [553]

Answer:

Reflection of sound waves also leads to echoes. Echoes are different than reverberations. Echoes occur when a reflected sound wave reaches the ear more than 0.1 seconds after the original sound wave was heard. ... Reflection of sound waves off of curved surfaces leads to a more interesting phenomenon.

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3 years ago
Which theory explains that cussing in front of your grandparents or hugging a stranger would be okay to you based on social cont
Ainat [17]
Either concrete or cognitive
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