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3 years ago

Which scenario do robes an interaction between two different spheres

1 answer:

3 0

Terms such as separate spheres and domestic–public dichotomy refer to a social phenomenon, ... In Politics, Aristotle described two separate spheres in Greek society, the home

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Magnetic lines of force are unaffected by paper, glass, or plastic. True False

myrzilka [38]

I believe the answer is true.

I hope this helps :)

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4 years ago

Why are fuse wires not provided in an electric circute containing an electric cell

Basile [38]

Hey there,

Electric cells we use usually carry limited voltage. Here's an example: 1.5V. Really, there is no chance of any shot circuit. that's why MCB and fuse wires are not used in their circuit .

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3 years ago

The Sears Tower is nearly 400 m high. How long would it take a steel ball to reach the ground if dropped on the top? What will b

kipiarov [429]

Answers:

a) 9.035 s

b) -88.543 m/s

Explanation:

The described situation is related to vertical motion (especifically free fall) and the equations that will be useful are:

$y=y_{o}+V_{o}t+\frac{1}{2}gt^{2}$ (1)

$V=V_{o}+gt$ (2)

Where:

$y=0$ is the final height of the steel ball

$y_{o}=400 m$ is the initial height of the steel ball

$V_{o}=0$ is the initial velocity of the steel ball (it was dropped)

$V$ is the final velocity of the steel ball

$t$ is the time it takes to the steel ball to reach the ground

$g=-9.8 m/s^{2}$ is the acceleration due to gravity

<u>Knowing this, let's begin with the answers:</u>

<h2>a) Time it takes the steel ball to reach the ground</h2>

We will use equation (1) with the conditions listed above:

$0=y_{o}+\frac{1}{2}gt^{2}$ (3)

Isolating $t$ :

$t=\sqrt{\frac{-2y_{o}}{g}}$ (4)

$t=\sqrt{\frac{-2(400 m)}{-9.8 m/s^{2}}}$ (5)

$t=9.035 s$ (6)

<h2>b) Final velocity of the steel ball</h2>

We will use equation (2) with the conditions explained above and the calculaated time:

$V=gt$ (7)

$V=(-9.8 m/s^{2})(9.035 s)$ (8)

$V=-88.543 m/s$ (9) The negative sign indicates the direction of the velocity is downwards

3 0

3 years ago

A certain piece of metal (density 9.45 grams per cubic centimeter) has the shape of a hockey puck with a diameter of 13 cm and a

atroni [7]

Answer:

0.0195 m

Explanation:

$\rho _{p}$ = density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³

$d_{p}$ = diameter of hockey puck = 13 cm = 0.13 m

$h_{p}$ = height of hockey puck = 2.8 cm = 0.028 m

$\rho _{m}$ = density of mercury = 13.6 gcm⁻³ = 13600 kgm³

$d$ = depth of puck below surface of mercury

According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck

Weight of mercury displaced = Weight of puck

$\rho _{m} (0.25)(\pi d_{p}^{2} d ) g = \rho _{p} (0.25)(\pi d_{p}^{2} h_{p} ) g\\\rho _{m} ( d ) = \rho _{p} ( h_{p} )\\(13600) d = (9450) (0.028)\\d = 0.0195 m$

7 0

3 years ago

An oak block had the following dimension, 2 cm by 2 cm and 5 cm in height. A copper block had the same dimensions. The copper bl

antiseptic1488 [7]

Answer:

ρ_body = 1000 kg / m³

Explanation:

This is an exercise in fluid mechanics, specifically we must use the Archimedean principle, which states that the thrust is equal to the weight of the dislodged liquid.

In this case let's start by finding the volume of our body

oak block

v = l to h

v = 0.02 0.02 0.05

V = 2 10⁻⁵ m³

cooper block indicate that it has the same dimensions so its volume is the same, the total volume of the body is

V_total = 4 10⁻⁵ m³

as they indicate that the body is fully submerged there is a balance between weight and thrust

B - W = 0

the push is

B = ρ_fluid g V_total

the body weight is

ρ_body = M / V_total

M = ρ_body V_total

W = Mg

W = ρ_body V_total g

we substitute

ρ_fluid g V_total = ρ_body V_total g

ρ_body = ρ_fluid

in this case the body is in equilibrium in the fluid, in case the density of the body is greater than that of the fluid, the body sinks

Therefore the average density is equal to the density of the fluid, since since it is water the density is

ρ_body = 1000 kg / m³

8 0

3 years ago