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Gemiola [76]
3 years ago
5

How much work should be done to lift a 5kg brick to the height of 12m

Physics
2 answers:
Goshia [24]3 years ago
8 0

Answer: 588 joules

Explanation:

Work is done when force is applied on an object over a distance ( whether vertical or horizontal). It is measured in joules.

Thus, Workdone = Force X distance

- Vertical distance to be moved by the brick = 12 metres

- Mass of box = 5kg

- Acceleration due to gravity when box was lifted represented by g is a constant with value of 9.8m/s^2

Now, recall that Force = Mass x acceleration due to gravity

i.e Force = 5kg x 9.8m/s^2

Force = 49 Newton

So, Workdone = Force X Distance

Workdone = 49 Newton X 12 metres

Workdone = 588 joules

Thus, 588 joules of work was done.

zhenek [66]3 years ago
8 0

Answer:

588 j

Explanation:

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the signs of heat and work are; -Q and -W

Explanation:

The first law of thermodynamics is given by; ΔU = Q − W

where;

ΔU is the change in internal energy of a system,

Q is the net heat transfer (the sum of all heat transfer into and out of the system)

W is the net work done (the sum of all work done on or by the system).

Now, The system in this case is the tire and since the air gets warmer, heat must have left the system. Therefore Q is negative (-Q).

Since work is done by the system, W remains negative.

Thus, the signs of heat and work are; -Q and - W

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The part of earth where all living things are found is called the
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Hey Dude....

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This is ur answer.....

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2 years ago
The nebular theory also predicts that the cloud should heat up as it collapses. what physical law explains why it heats up?
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At which location would a bowling ball have the greatest weight?
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You drop your frozen rock from a green bridge. The frozen rock starts from rest (initial velocity = 0ms). The rock takes 4.3s to
valentinak56 [21]

Answer:

The velocity of the frozen rock at t = 1.5\,s is -14.711 meters per second.

Explanation:

The frozen rock experiments a free fall, which is a type of uniform accelerated motion due to gravity and air viscosity and earth's rotation effect are neglected. In this case, we need to find the final velocity (v), measured in meters per second, of the frozen rock at given instant and whose kinematic formula is:

v = v_{o} + g\cdot t (Eq. 1)

Where:

v_{o} - Initial velocity, measured in meters per second.

g - Gravity acceleration, measured in meters per square second.

t - Time, measured in seconds.

If we get that v_{o} = 0\,\frac{m}{s}, g = -9.807\,\frac{m}{s^{2}} and 1.5\,s, then final velocity is:

v = 0\,\frac{m}{s}+\left(-9.807\,\frac{m}{s^{2}} \right) \cdot (1.5\,s)

v = -14.711\,\frac{m}{s}

The velocity of the frozen rock at t = 1.5\,s is -14.711 meters per second.

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