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xenn [34]
3 years ago
8

4.-Una atleta patea un balon (masa de 650gr y angulo de 45 grados) arriba de un edificio con una velcidad 21 m/s, el edificio mi

de 10 metros de altura. Si el balon cae fuera del edificio, calcula la velocidad (m/s) que este alcanza un instante antes de tocar el suelo
Physics
1 answer:
marta [7]3 years ago
3 0

Answer:

v = 25 m/s

Explanation:

½mv₀² + mgh = ½mv₁²

v₁² = v₀² + 2gh

v₁ = √(21² + 2(9.8)(10))

v₁ = 25.238858..

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ahrayia [7]
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5 0
2 years ago
If the current in a wire increases from 5 A to 10 A, what happens to its magnetic field? If the distance of a charged particle f
Anna007 [38]

(1) Doubling of the current through the wire will result in doubling of its magnetic  field.

The magnetic field around a wire is a function of the current I and radial distance r

B = \frac{\mu\cdot I }{2\pi r}

(with mu denoting the magnetic permeability of the medium). So, B is directly proportional to I. The field magnitude will double with the doubled current from 5A to 10A

(2) Using the same formula as in (1), we can see that the magnetic field is inversely proportional to the radial distance from the wire. So, a particle at 20cm will experience half the magnitude compared to a particle at 10cm.

(3) Answer

If a particle with a charge q  moves through a magnetic field B with velocity v, it will be acted on by the magnetic force

F_m = B\cdot v\cdot q

So, a particle with charge -2uC will experience a magnetic force of same magnitude but opposite direction (and perpendicular to B) as compared to a particle with a charge of 2uC

3 0
2 years ago
Read 2 more answers
If an object looses electrons, then have been transferred
slava [35]
If<span> a neutral </span>object loses<span> some </span>electrons<span>, </span>then<span> it will possess more protons</span>
4 0
3 years ago
A runner of mass 56.0kg runs around the edge of a horizontal turntable mounted on a vertical, frictionless axis through its cent
SCORPION-xisa [38]

Answer: -0.84 rad/sec (clockwise)

Explanation:

Assuming no external torques act on the system (man + turntable), total angular momentum must be conserved:

L1 = L2

L1 = It ω + mm. v . r = 81.0 kg . m2 .21 rad/s – 56.0 kg. 3.1m/s . 3.1 m  

L1 = -521.15 kg.m2/sec (1)

(Considering to the man as a particle that is moving opposite to the rotation of  the turntable, so the sign is negative).

Once at rest, the runner is only a point mass with a given rotational inertia respect from the axis of rotation, that can be expressed as follows:

Im = m. r2 = 56.0 kg. (3.1m)2 = 538.16 kg.m2

The total angular momentum, once the runner has come to an stop, can be written as follows:

L2= (It + Im) ωf = -521.15 kg.m2/sec  

L2= (81.0 kg.m2 + 538.16 kg.m2) ωf = -521.15 kg.m2/sec  

Solving for ωf, we get:

ωf = -0.84 rad/sec  (clockwise)

5 0
2 years ago
Which of the following objects is an example of a luminous source?
Korvikt [17]

Answer:

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In physics, that would be the answer.

7 0
2 years ago
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