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nikklg [1K]
3 years ago
5

Deloria says she can find the relative frequency of nuts based on another relative frequency. What might she be doing?

Mathematics
1 answer:
forsale [732]3 years ago
3 0

Answer:

frequency of nuts based on another relative frequency. What might

she be doing

nuts:3/30=15%

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One pretzel has 20 calories. Write an algebraic expression for the total number of calories in n pretzels.
vredina [299]

Answer:

20n

Step-by-step explanation:

One pretzel has 20 calories. Write an algebraic expression for the total number of calories in n pretzels.

1 pretzel = 20 calories

n pretzel = x

Cross Multiply

x × 1 pretzel = n pretzel × 20 calories

x = n pretzel × 20 calories/1 pretzel

x = 20 n

Therefore, an algebraic expression for the total number of calories in n pretzels = 20n

4 0
3 years ago
A political adviser stood at the corner of 1st Avenue and Main Street and asked every 10th person who walked past if they intend
krok68 [10]

Answer:

Voluntary response

Step-by-step explanation:

Because the politival adviser deliberately chosen a reaction to a stimulus that may require a complex coordination of excitatory and inhibitory impulses with feedback from visual, motor, and other systems.

8 0
2 years ago
A survey asked the question, “Do you think a vaccination should be mandatory to enter shopping areas?!” to a random sample of 10
Sergio [31]

Answer: no it shouldn’t

Step-by-step explanation:

7 0
2 years ago
How many kilograms is a rice packet that weighs 750 g?<br> (Please answer quick!)
RideAnS [48]

Answer:

0.750 kg

Step-by-step explanation:

Hi there ,

As you know 1 kg = 1000g

So when we convert g to kg then we divide the given value of grams by 1000.

So in this case we have 750 grams, changing it we have :

\frac{750}{1000}

Since there are 3 zeroes in 1000 we move the decimal point by 3 places to the left leaving the answer as : 0.750 kg or \frac{750}{1000} kg

Please mark me as brainliest if you found the above answer helpful

5 0
2 years ago
I need help on #10
Ede4ka [16]
D = sq.root of((x2 - x1)^2 + (y2 - y1)^2)
sq.root of 13 = sq.root of((x - (-2))^2 + (1 - 3)^2)
= sq.root of((x + 2)^2 + (-2)^2)
= sq.root of (x^2 + 4x + 4 + 4)
= sq.root of (x^2 + 4x + 8)

Now if we square both sides:
x^2 + 4x + 8 = 13
x^2 + 4x - 5 = 0
(x + 5)(x - 1) = 0
x = -5 or x = 1
6 0
3 years ago
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