Answer:
a. t = 1.43 s
b. d = 7.88 m
Explanation:
a. The time of flight can be found using the following equation:
Where:
: is the final height = -10 m
: is the initial height = 0
: is the initial speed in the vertical direction = 0
g: is the acceleration due to gravity = 9.81 m/s²
By solving the above equation for "t" we have:
Hence, the ball will hit the ground in 1.43 s.
b. The distance in the horizontal direction can be found as follows:
Where:
x₀: is the initial position in the horizontal direction = 0
a: is the acceleration in the horizontal direction = 0 (it is moving at constant speed)
Therefore, the ball will travel 7.88 m before it hits the ground.
I hope it helps you!
Answer:
3 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 2 L
Initial pressure (P₁) = 0.75 atm
Final pressure (P₂) = 0.5 atm
Final volume (V₂) =?
Using the Boyle's law equation, the new volume (i.e final volume) of the Ne gas can be obtained as:
Initial volume (V₁) = 2 L
Initial pressure (P₁) = 0.75 atm
Final pressure (P₂) = 0.5 atm
Final volume (V₂) =?
P₁V₁ = P₂V₂
0.75 × 2 = 0.5 × V₂
1.5 = 0.5 × V₂
Divide both side by 0.5
V₂ = 1.5 / 0.5
V₂ = 3 L
Thus, the new volume of the Ne gas is 3 L
Answer:
7.35 J
Im assuming, upon answering the question, that the gravity in this scenario is 9.8? As 9.8 is the gravitational force upon the earth.
Answer: Exercise Physiology
Explanation:
Answer:
A. 24 m, 14 m/s
B. 8.0 m
Explanation:
Given:
x₀ = 6.0 m
v₀ = 4.0 m/s
a = 5.0 m/s²
t = 2.0 s
A. Find: x and v
x = x₀ + v₀ t + ½ at²
x = (6.0 m) + (4.0 m/s) (2.0 s) + ½ (5.0 m/s²) (2.0 m/s)²
x = 24 m
v = at + v₀
v = (5.0 m/s²) (2.0 s) + (4.0 m/s)
v = 14 m/s
B. Find x when v = 6.0 m/s.
v² = v₀² + 2a (x − x₀)
(6.0 m/s)² = (4.0 m/s)² + 2 (5.0 m/s²) (x − 6.0 m)
x = 8.0 m
