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zhuklara [117]
3 years ago
12

True or false: Earth's gravitational force pulls the moon towards it while the sun pushes Earth away from it

Physics
1 answer:
Inessa05 [86]3 years ago
3 0

Answer:

false

Explanation:

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Doug is driving a golf ball off the tee. His downswing takes 0.50sec from the top of the swing until ball impact. At the top of
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D.eeeeeeezzzzzzzz nuuuuutttttssss!
6 0
3 years ago
You have been hired as a technical consultant for an early-morning cartoon series for children to make sure that the science is
katen-ka-za [31]

The initial potential energy of the wagon containing gold boxes will enable

it roll down the hill when cut loose.

The Lone Ranger and Tonto have approximately <u>5.1 seconds</u>.

Reasons:

Mass wagon and gold = 166 kg

Location of the wagon = 77 meters up the hill

Slope of the hill = 8°

Location of the rangers = 41 meters from the canyon

Mass of Lone Ranger, m₁ = 65 kg

Mass of Tonto m₂ = 66 kg

Solution;

Height of the wagon above the level ground, h = 77 m × sin(8°) ≈ 10.72 m

Potential energy = m·g·h

Where;

g = Acceleration due to gravity ≈ 9.81 m/s²

Potential energy of wagon, P.E. ≈ 166 × 9.81 × 10.72 = 17457.0912

Potential energy of wagon, P.E. ≈ 17457.0912 J

By energy conservation, P.E. = K.E.

K.E. = \mathbf{\dfrac{1}{2} \cdot m \cdot v^2}

Where;

v = The velocity of the wagon a the bottom of the cliff

Therefore;

\dfrac{1}{2} \times 166 \times v^2 = 17457.0912

v = \sqrt{\dfrac{17457.0912}{\dfrac{1}{2} \times 166} } \approx 14.5

Velocity of the wagon, v ≈ 14.5 m/s

Momentum = Mass, m × Velocity, v

Initial momentum of wagon = m·v

Final momentum of wagon and ranger = (m + m₁ + m₂)·v'

By conservation of momentum, we have;

m·v = (m + m₁ + m₂)·v'

\therefore v' = \mathbf{ \dfrac{m \cdot v}{(m + m_1 + m_2)  }}

Which gives;

\therefore v' = \dfrac{166 \times 14.5}{(166 + 65 + 66)  } \approx 8.1

The velocity of the wagon after the Ranger and Tonto drop in, v' ≈ 8.1 m/s

Time = \dfrac{Distance}{Velocity}

\mathrm{The \ time \ the\ Lone \  Ranger \  and  \ Tonto \  have,  \ t} = \dfrac{41 \, m}{8.1 \, m/s} \approx 5.1 \, s

The Lone Range and Tonto have approximately <u>5.1 seconds</u> to grab the

gold and jump out of the wagon before the wagon heads over the cliff.

Learn more here:

brainly.com/question/11888124

brainly.com/question/16492221

5 0
3 years ago
Do I fill this chart right? Can you please check if I am wrong or not?
luda_lava [24]

Physical properties of water:

Color: No color/colorless.

Odor: Odorless.

Taste: Tasteless.

Density: 1 g/ml.

Boiling point: 100°C.

Freezing/Melting point: 0°C.

State or phase:

Vapor: Gas.

Room temperature: Liquid.

Ice: Solid.

Hence, water is a colorless, odorless, and tasteless substance whose density is 1 g/ml. It boils at 100°C and melts at 0°C. In the vapor phase, it is in a gaseous state, at room temperature, it exists in a liquid state, and when its freezes (ice) it's in the solid state.

7 0
2 years ago
A proton is released in a uniform electric field, and it experiences an electric force of 2.04×10−14 N toward the south.
Lemur [1.5K]

Answer:

Part A:

E=127500N/C\\E=1.275*10^{5} N/C

Part B:

Option B (Towards the South)

Explanation:

Part A:

Magnitude if electric field E:

E=Force/charge

Force=2.04×10−14 N

Charge=1.6×10−19 C

E=\frac{2.04*10^{-14}}{1.6*10^{-19}} \\E=127500N/C\\E=1.275*10^{5} N/C

Part B:

Option B (Towards the South)

As electron is experiencing the force towards south,it means the direction of the electric field is towards the south because direction of field lines is from positive to negative, so proton is moving towards south it means negative charge is in south to which proton is attracted. So electric field is towards South.

7 0
4 years ago
Select the correct statement about the flow of power as a function of time between a balanced three-phase source and a balanced
Akimi4 [234]

Answer:

Total power flow in a balanced system is constant with time

Therefore, the torque required to a balance load is constant and the vibration is lessened

Explanation:

3 0
3 years ago
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