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4 years ago

7

State the universal law of gravitation

1 answer:

LuckyWell [14K]4 years ago

7 0

Newton's law of universal gravitation states that the force of gravity acts between all objects in the universe. Any two objects that have a finite mass exert an attractive force on each other....
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Hope it helps !!!</span>

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CAN SOMEONE EXPLAIN HOW TO DO THIS?!?!

Rzqust [24]

Both cars are canceling out the energy of each other. The energy that is left over because one car has a bigger kinetic energy is the energy that is going to move BOTH the cars.

First Car : <em>0.5 * 2000kg * 3m/s^2 = 10.24 KJ</em>

Second Car :<em> 0.5 * 2000kg * 2m/s^2 = 4 KJ</em>

Leftover Energy : <em>10.24 KJ - 4 KJ = 6.24 KJ
</em>
Movement of BOTH cars :<em /><em>
6.24 = 4000kg * v^2
</em>v = √(6.24 / 4000) =0.04 m/s = 4 cm/s

3 0

4 years ago

A 3 kg ball is rolling 2 m/s. How much kinetic energy does it have?

vova2212 [387]

Answer:

6

Explanation:

0.5(3 × 2^2)

4 0

3 years ago

A river flows due south with a speed of 2.0 m/s .You steer a motorboat across the river; your velocity relative to the water is

mihalych1998 [28]

Answer:

a) $v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s$

b) $\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62$ degrees and on this case to the South of the East.

c) $t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s$

d) $Y = 2 m/s * 125 s = 250m$

So it would be 250 to the South

Explanation:

Part a

For this case the figure attached shows the illustration for the problem.

We know that $v_y = 2 m/s$ represent the velocity of the river to the south.

We have the velocity of the motorboard relative to the water and on this case is $V_x= 4.8 m/s$

And we want to find the velocity of the motord board relative to the Earth $v_m$

And we can find this velocity from the Pythagorean Theorem.

$v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s$

Part b

We can find the direction with the following formula:

$\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62$ degrees and on this case to the South of the East.

Part c

For this case we can use the following definition

$D = Vt$

The distance would be D = w = 600 m and the velocity V = 4.8m/s and if we solve for t we got:

$t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s$

Part d

For this case we can use the same definition but now using the y compnent we have:

$Y = v_y t$

And replacing we got:

$Y = 2 m/s * 125 s = 250m$

So it would be 250 to the South

7 0

3 years ago

A student releases a ball from rest on an inclined plane and measures that it travels a distance of 0.6 m in a time of 4.0 s. Fi

Korvikt [17]

The average speed of the ball is 0.15 m/s.

The average speed of the ball can be calculated using the formula below.

<h3 /><h3> Average speed: </h3>

This is the ratio of the total distance to the total time traveled by a body

<h3 /><h3>Formula:</h3>

S = d/t.................. Equation 1

<h3>Where:</h3>

S = Average speed
d = total distance
t = total time.

From the question,

<h3>Given:</h3>

d = 0.6 m
t = 4.0 s

Substitute these values into equation 1

S = 0.6/4
S = 0.15 m/s

Hence, the average speed of the ball is 0.15 m/s.

Learn more about average speed here: brainly.com/question/4931057

8 0

2 years ago

1. What are examples of muscle endurance activities/exercises? 2. Which sports require the most muscle endurance? 3. How many si

Komok [63]

Answer:

hello i need points i need to pass 8th grade

Explanation:

4 0

3 years ago

Read 2 more answers