Answer:
Explanation:
a ) Let T be tension in the horizontal cable .
Taking torque about hinge of weight and tension
45000 x 7 x cos37 = 3.5 sin 37 x T
T = 119431 N
b ) If R be the reaction force on the hinge
R sin 37 = 45000 ( vertical force balancing each other )
R = 74775 N
c ) The direction of R will be along the bridge
d ) Moment of inertia of bridge
I = Ml² / 3 = (45000 / 9.8 ) x 14² / 3
= 300000.
When cable breaks , the weight creates a torque about the hinge will creates angular acceleration
Torque by weight about the hinge
= 45000 x 7 x cos 37
= 251570
angular acceleration = torque / moment of inertia
= 251570 / 300000
= .84 radian / s²
Jjjhgggghujjnnbcxxddrtyyujjnn.
Answer:
11970 pa
Explanation:
A millimetre of mercury is a manometric unit of pressure, formerly defined as the extra pressure generated by a column of mercury one millimetre high, and currently defined as exactly 133.322387415 pascals so if 1 mmHg is 133 pa 90mmHg is 11970 aprox
Answer:
The amplitude of the subsequent oscillations is 13.3 cm
Explanation:
Given;
mass of the block, m = 1.25 kg
spring constant, k = 17 N/m
speed of the block, v = 49 cm/s = 0.49 m/s
To determine the amplitude of the oscillation.
Apply the principle of conservation of energy;
maximum kinetic energy of the stone when hit = maximum potential energy of spring when displaced
Therefore, the amplitude of the subsequent oscillations is 13.3 cm
