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maxonik [38]
2 years ago
7

X/-9 =3I dont understand this.​

Mathematics
2 answers:
STatiana [176]2 years ago
5 0

Final Answer: x = -27

Steps/Equations:

Question: \frac{x}{-9} = 3

Step 1: Move the negative sign to the left side.

-\frac{x}{9} = 3

Step 2: Multiply both sides by 3.

-x = 3 * 9

Step 3: Simplify 3 * 9 to 27.

-x = 27

Step 4: Multiply both sides by -1.

x = -27

~I hope I helped :)~

stellarik [79]2 years ago
4 0

Answer:

x = -27

Step-by-step explanation:

x / 9 =3

multiply both sides by -9

x = -27

Hope this helps!!

Happy Holidays!!

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Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations
marusya05 [52]

Answer:

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Step-by-step explanation:

Given

I will answer this question using the attached triangle

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Substitute values for BC and BA

Sin \angle A =\frac{8cm}{10cm}

Sin \angle A =\frac{8}{10}

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Cos \angle A=\frac{AC}{BA}

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Cos \angle A=\frac{6cm}{10cm}

Cos \angle A=\frac{6}{10}

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Solving (b): Sine and Cosine B

In trigonometry:

Sin \theta =\frac{Opposite}{Hypotenuse} and

Cos \theta =\frac{Adjacent}{Hypotenuse}

So:

Sin \angle B =\frac{AC}{BA}

Substitute values for AC and BA

Sin \angle B =\frac{6cm}{10cm}

Sin \angle B =\frac{6}{10}

Sin \angle B =0.60

Cos \angle B=\frac{BC}{BA}

Substitute values for BC and BA

Cos \angle B=\frac{8cm}{10cm}

Cos \angle B=\frac{8}{10}

Cos \angle B=0.80

Using a calculator:

A = 53^{\circ}

So:

Sin(53^{\circ}) =0.7986

Sin(53^{\circ}) =0.80 -- approximated

Cos(53^{\circ}) = 0.6018

Cos(53^{\circ}) = 0.60 -- approximated

B = 37^{\circ}

So:

Sin(37^{\circ}) = 0.6018

Sin(37^{\circ}) = 0.60 --- approximated

Cos(37^{\circ}) = 0.7986

Cos(37^{\circ}) = 0.80 --- approximated

8 0
3 years ago
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6 0
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Answer:

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