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zysi [14]
2 years ago
13

You toss a ball up at a speed of 25 m/s. How long will it take for the ball to reach

Physics
1 answer:
erik [133]2 years ago
3 0

Answer:

0.ms

Explanation:

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PLEASE HELP ME WITH THIS ONE QUESTION
ki77a [65]

Answer:

B) The current of the entire circuit is lowered.

Explanation:

There are two ways in which a resistor can be connected in a circuit;

i) Series: In a series connection, resistors are connected end to end. In this arrangement, the current passing through each resistor is the same while the potential difference across each resistor is different.

ii) Parallel: In a parallel connection, resistors are connected to  common junctions. In this arrangement, the potential difference across each resistor is the same while the current across each resistor varies.

In a series circuit, the effective resistance is the algebraic sum of resistance of all the resistors connected in series. Hence, if a large resistor is connected in series, the effective resistance of the circuit is greatly increased.

Since the voltage is given by;

V=IR (Ohm's law)

Where R is the effective resistance

Then;

I = V/R

If R becomes very large due to a large resistance connected in series, then the current of the entire circuit is lowered.

6 0
3 years ago
If the diameter of the space station is 730 m , how many revolutions per minute are needed for the "artificial gravity" accelera
nignag [31]
For circular motion we know that

<span>F=ma=v^2/r </span>

<span>Therefore: </span>

<span>v = sqrt (rma) </span>

<span>Also, for cicular motion: </span>

<span>rev/min. = 60v/(2r*pi) </span>

<span>So your equation is: </span>

<span>rev./min = 60sqrt(rma)/(2pi*r) </span>

<span>For the mass (m) we can just use 1 kg. 
</span>
rev./min = 60sqrt(730*1*9.8)/(2pi*730) =60sqrt(7154)/(4584.4) 
rev./min = 60sqrt(7154)/(4584.4) =1.11 rev/min
<span>
the answer is </span>1.11 rev/min<span>

 </span>
4 0
3 years ago
In order to do work, the force vector must be
aliina [53]

in the same direction as the displacement vector and the motion

5 0
3 years ago
A 0.0427 kg racquet-ball is moving
Gwar [14]

Answer:

Mass of the box = 0.9433 kg

Explanation:

Mass of racket-ball (m_1) = 0.00427 kg

Velocity of racket-ball before collision (v_{1i}) = 22.3 m/s

Velocity of racket-ball after collision with box (v_{1f}) = -11.5 m/s

[Since ball is bouncing back, so velocity is taken negative.]

Velocity of the box before collision v_{2i} = 0 m/s

<em>[Since the box is stationary, so velocity is taken zero]</em>

Velocity of box moving forward after collision v_{2f}= 1.53 m/s

To find the mas of the box m_2.

By law of conservation of momentum we have:

Momentum before collision = Momentum after collision

This can be written as:

p_i=p_f

m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}

We can plugin the given value to find m_2

(0.0427\times 22.3)+(m_2\times 0)=(0.0427\times (-11.5))(m_2\times 1.53)

0.9522+0=-0.4911+1.53m_2

Adding both sides by 0.4911

0.9522+0.4911=-0.4911+0.4911+1.53m_2

1.4433=1.53m_2

Dividing both sides by 1.53.

\frac{1.4433}{1.53}=\frac{1.53m_2}{1.53}

0.9433=m_2

∴ m_2=0.9433 kg

Mass of the box = 0.9433 kg (Answer)

4 0
3 years ago
Find the value of a x , the x-component of the object's acceleration.
jok3333 [9.3K]
To find the x component use the following formula, where Ф = theta = the angle 'a' makes with the x axis.

a_x = a*cos(theta)

3 0
3 years ago
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