To solve this problem we will apply the concepts related to the Force of gravity given by Newton's second law (which defines the weight of an object) and at the same time we will apply the Hooke relation that talks about the strength of a body in a system with spring.
The extension of the spring due to the weight of the object on Earth is 0.3m, then


The extension of the spring due to the weight of the object on Moon is a value of
, then

Recall that gravity on the moon is a sixth of Earth's gravity.




We have that the displacement at the earth was
, then


Therefore the displacement of the mass on the spring on Moon is 0.05m
Answer:D
Explanation:
Given
mass of object 
Distance traveled 
velocity acquired 
conserving Energy at the moment when object start falling and when it gains 12 m/s velocity
Initial Energy
Final Energy

where
is friction work if any


Since Friction is Present therefore it is a case of Open system and net external Force is zero
An open system is a system where exchange of energy and mass is allowed and Friction is acting on the object shows that system is Open .
Solution :
The motion in the y direction.
The time taken by the toy rocket to hit the ground,

S = distance travelled = 30 m
u = 0 m/s
a = 
t= time in seconds
Therefore, 
t = 2.47 sec
Now motion in the x direction,
u = 12 m/sec

Upon integration 'v' with respect to 't'

Once again integrating with respect to t,


= 0.0176+29.64
= 29.65 m
Therefore, the toy rocket will hit the ground at 29.65 m from the building.
The answer in (B)214.4J
I hope this helped have a nice day!
Answer:
The number of people at game are approximately 22909
Explanation:
Given data
When one person shout 
When n number of person shout together 
The sound intensity level during one person shout is given by:

The sound intensity level during n number of person shout is given by:

Since each person generates same sound intensity and hence total number of persons can be determined as

Hence
The number of people at game are approximately 22909