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3 years ago

Describe how the potential energy of a river is changed into kinetic energy.

Physics

1 answer:

daser333 [38]3 years ago

8 0

Answer:

The energy possessed by a river when it is on top of a hill or a water fall is the potential energy . That is , as long as water is at some height above the ground level, it will have potential energy due to the influence of gravity . But once it starts flowing, the motion or movement is responsible for the kinetic energy.

Explanation:

Energy due to the position or state of an object is gravitational potential energy. Once the object starts moving, it has a certain velocity. Velocity possessed by a mass ( or an object ) will give rise to kinetic energy.

For a given object, It is conservation of energy which basically explains this. The total energy should always remain constant during a process.

For the river waters, the potential energy due to its state is converted to kinetic energy of its motion.

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Explanation:

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3 years ago

A car accelerates from 30 m/s to 50 m/s in 2 seconds. Calculate the cars acceleration

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Answer:

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3 years ago

A positive charge of 8.0 × 10-4 C is in an electric field that exerts a force of 3.5 × 10-4 N on it. What is the strength of the

Gennadij [26K]

Answer:

E = 0.437 N/C

Explanation:

Given that,

Charge, $q=8\times 10^{-4}\ C$

Electric force, $F=3.5\times 10^{-4}\ N$

Let the strength of the electric field is E. We know that, the electric force is given by :

F = qE

Where

E is the electric field strength

$E=\dfrac{F}{q}\\\\E=\dfrac{3.5\times 10^{-4}}{8\times 10^{-4}}\\E=0.437\ N/C$

So, the strength of the electric field is equal to 0.437 N/C.

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3 years ago

A thin uniform rod of mass M and length L is bent at its center so that the two segments are now perpendicular to each other. Fi

Tatiana [17]

Answer:

(a) I_A=1/12ML²

(b) I_B=1/3ML²

Explanation:

We know that the moment of inertia of a rod of mass M and lenght L about its center is 1/12ML².

(a) If the rod is bent exactly at its center, the distance from every point of the rod to the axis doesn't change. Since the moment of inertia depends on the distance of every mass to this axis, the moment of inertia remains the same. In other words, I_A=1/12ML².

(b) The two ends and the point where the two segments meet form an isorrectangle triangle. So the distance between the ends d can be calculated using the Pythagorean Theorem:

$d=\sqrt{(\frac{1}{2}L) ^{2}+(\frac{1}{2}L) ^{2} } =\sqrt{\frac{1}{2}L^{2} } =\frac{1}{\sqrt{2} } L=\frac{\sqrt{2} }{2} L$

Next, the point where the two segments meet, the midpoint of the line connecting the two ends of the rod, and an end of the rod form another rectangle triangle, so we can calculate the distance between the two axis x using Pythagorean Theorem again:

$x=\sqrt{(\frac{1}{2}L)^{2}-(\frac{\sqrt{2}}{4}L) ^{2} } =\sqrt{\frac{1}{8} L^{2} } =\frac{1}{2\sqrt{2}} L=\frac{\sqrt{2}}{4} L$

Finally, using the Parallel Axis Theorem, we calculate I_B:

$I_B=I_A+Mx^{2} \\\\I_B=\frac{1}{12} ML^{2} +\frac{1}{4} ML^{2} =\frac{1}{3} ML^{2}$

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