1) 211m/s
2)240<span>°
3)759,600m or 759.6 km</span>
We can apply the law of conservation of energy here. The total energy of the proton must remain constant, so the sum of the variation of electric potential energy and of kinetic energy of the proton must be zero:

which means

The variation of electric potential energy is equal to the product between the charge of the proton (q=1eV) and the potential difference (

):

Therefore, the kinetic energy gained by the proton is

<span>And since the initial kinetic energy of the proton was zero (it started from rest), then this 1000 eV corresponds to the final kinetic energy of the proton.</span>
Answer:
The answer to your question is Ke = 72 J
Explanation:
Kinetic energy depends on the speed of and object and its mass.
Data
mass = m = 4 kg
speed = v = 6 m/s
distance = d = 8 m
Kinetic energy = ke = ?
Formula
Ke = (1/2) mv²
Substitution
Ke = (1/2) (4)(6)²
Simplification
Ke = (1/2)(4)(36)
Ke = (1/2)(144)
Ke = 72 Joules
Result
Ke = 72 J
As per Einstein's relation of relativity

here we know that


now here we know that

now from above equation mass of the muon is given as


now for the momentum of muon we can use



so above is the momentum of muon