A copper forms a patina when it interacts with air
Answer:
V at C is 3.6 m/s
Explanation:
At A kinetic energy is zero and potential energy=mgh=0.5*9.81*0.6=2.943 J
By conservation of energy.
KE+PE=Constant
At C PE=0.6 J
the KE=2.943-0.6=2.343 J
KE=0.5*m*v^2
v=√[KE/(0.5*m)]=3.06 m/s
Answer: 4.4 cm.
Explanation:
Rise of water in the smaller tube= h1=8.8 centimeter(cm)
Radius of the smaller tube= r
Rise of water in the larger tube= h2 (in centimeter).
The radius of the larger tube is twice that of the smaller tube means that;
The radius in the larger tube is 2r ( 2 multiply by the radius r, of the smaller tube)
Using Jurin's law;
height or rise of liquid is inversely proportional to its radius, r.
That is; hr= constant.
Therefore, we have;
h1 × r1 = h2 × r2.
Rise in smaller tube × radius of the smaller tube = height of the larger tube × radius of the larger tube.
8.8 cm × r = h2 × 2r
= (8.8cm)r = (h2) 2r
Divide both sides by 2r, we then have;
8.8cm r/ 2r = h2
h2= 4.4cm
Therefore, the height or rise in large tube is half of that of the smaller tube.
Roughly 1609 meters in one mile
