Question

A mineral sample has a mass of 35 g. When it is dropped into a graduated cylinder with 25mL of water, the volume of the water rises to 35 mL. Using this data, determine the density of the sample.

Answer 1

Answer:

$\boxed {\boxed {\sf 3.5 \ g/mL}}$

Explanation:

The density of an object is the mass per unit volume, so the formula is:

$\rho= \frac {m}{v}$

We know the mass of the mineral sample is 35 grams.

We have to calculate the volume. The volume was found using water displacement. An amount of water was put in a graduated cylinder, then the object was dropped in. The volume is the difference between the final water level and the initial water level.

• v= final water - initial water
• v= 35 mL - 25 mL
• v= 10 mL

Now we know the mass and volume of the mineral sample.

• m= 35 g
• v= 10 mL

Substitute the values into the formula.

$\rho= \frac{35 \ g}{10 \ mL}$

Divide.

$\rho = 3.5 \ g/mL$

The density of the mineral sample is 3.5 grams per milliliter.

Answer 2

Answer:

3.5g/ml

Explanation:

density=mass/volume

the mass of the mineral we have been given to be 35g

and it's volume is found by subtracting the initial volume from the final volume which is 35ml-25ml=10ml