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3 years ago

Ok so how do i determine how many point i wanna give out on a question

Physics

2 answers:

Leviafan [203]3 years ago

7 0

Explanation:

when ever you ask a question and you pick the subject and the grade level it shows points you will see 10 and above numbers so that is how know how many points you given have a good day

Sergeu [11.5K]3 years ago

4 0

Sometimes it just picks for you

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Which graphs show the correct relationship between kinetic energy and mass?

Anettt [7]

Kinetic Energy:
Kinetic Energy is the energy of motion.

Mass:
Mass is the number of particles that a substance has

I think the correct graph would be
the THIRD GRAPH

5 0

3 years ago

Read 2 more answers

explain a ball is pitched east at a speed of 40 km/h. the batter hits it west at a speed of 40 km/h.did the ball accelerate

Slav-nsk [51]

Yep, uh-huh, indeed, indubitably, and you better believe it.
The ball did accelerate.

Acceleration means any one of these:
-- speeding up
-- slowing down
-- changing direction .

The direction of the ball changed from east to west.
That's acceleration right there.
_____________________________________

Acceleration means any change of velocity.
Velocity is speed and direction.

The velocity of the ball changed from (40 km/hr east) to (40 km/hr west).

The change in velocity was 80 km/hr to the west.

5 0

3 years ago

A sample of polonium-210 was left for 414 days.

jenyasd209 [6]

Answer:

PO(1) = PO(0) / 2 1 refers to 1 half life of PO(0)

PO(2) = PO(1) / 2 = P(0) / 4 amount of PO left after 2 half-lives

PO(3) = PO(2) / 2 = PO(0) / 8 amount of PO left after 3 half-lives

414 da / 138 da = 3 3 half-lives pass in 414 da

PO(0) = 8 PO(3) = 8 * 1.45E-4 g = 1.16E-3 g = .00116 g after 414 days

6 0

3 years ago

At one instant a bicyclist is 21.0 m due east of a park's flagpole, going due south with a speed of 13.0 m/s. Then 21.0 s later,

andre [41]

Answer:

Part a)

$d = 21\sqrt2 = 29.7 m$

Part b)

Direction is 45 degree North of West

Part c)

$v_{avg} = 1.41 m/s$

Part d)

direction of velocity will be 45 Degree North of West

Part e)

$a = 0.875 m/s^2$

Part f)

$\theta = 45 degree$ North of East

Explanation:

Initial position of the cyclist is given as

$r_1 = 21.0 m$ due East

final position of the cyclist after t = 21.0 s

$r_2 = 21.0 m$ due North

Part a)

for displacement we can find the change in the position of the cyclist

so we have

$d = r_2 - r_1$

$d = 21\hat j - 21\hat i$

so magnitude of the displacement is given as

$d = 21\sqrt2 = 29.7 m$

Part b)

direction of the displacement is given as

$\theta = tan^{-1}\frac{y}{x}$

$\theta = tan^{-1}\frac{21}{-21}$

so it is 45 degree North of West

Part c)

For average velocity we know that it is defined as the ratio of displacement and time

so here the magnitude of average velocity is defined as

$v_{avg} = \frac{\Delta x}{t}$

$v_{avg} = \frac{29.7}{21}$

$v_{avg} = 1.41 m/s$

Part d)

As we know that average velocity direction is always same as that of average displacement direction

so here direction of displacement will be 45 Degree North of West

Part e)

Here we also know that initial velocity of the cyclist is 13 m/s due South while after t = 21 s its velocity is 13 m/s due East

So we have

change in velocity of the cyclist is given as

$\Delta v = v_f - v_i$

$\Delta v = 13\hat i - (-13\hat j)$

now average acceleration is given as

$a = \frac{\Delta v}{\Delta t}$

$a = \frac{13\hat i + 13\hat j}{21}$

so the magnitude of acceleration is given as

$a = \frac{13\sqrt2}{21} = 0.875 m/s^2$

Part f)

direction of acceleration is given as

$\theta = tan^{-1}\frac{y}{x}$

$\theta = tan^{-1}\frac{13}{13}$

$\theta = 45 degree$ North of East

4 0

3 years ago

Understand how to apply the equations for 1-dimensional motion to the y and x directions separately in order to derive standard

dexar [7]

Answer:

the equations of motion can be separated into an equation that depends on a single variable.

Explanation:

he one-dimensional kinematics equations can be applied to two-dimensional systems because we can write the equations in such a way that each one of them depends on variables in a single dimension plus time, which, because it is a scalar, can be used in all dimensions.

A mathematical way of saying this is that the equations of motion can be separated into an equation that depends on a single variable.

8 0

3 years ago