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3 years ago

What is the total force of an object which has a mass of 150kg and is accelerating at 2m/s/s?

Physics

1 answer:

fredd [130]3 years ago

6 0

Answer:

$\boxed {\boxed {\sf 300 \ Newtons }}$

Explanation:

Force can be found by multiplying the mass by the acceleration.

$F=ma$

The mass is 150 kilograms and the acceleration is 2 meters per second per second, or 2 meters per square second.

$m= 150 \ kg \\a= 2 \ m/s^2$

Substitute the values into the formula.

$F= 150 \ kg * 2 \ m/s^2$

Multiply.

$F= 300 \ kg*m/s^2$

We know that 1 kilogram meter per square second is equal to 1 Newton.
Therefore our answer of 300 kg*m/s² is equal to 300 N

$F= 300 \ N$

The force of the object is <u>300 Newtons.</u>

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Two speakers are 3.0 m apart and play identical tones of frequency 170 Hz. Sam stands directly in front of one speaker at a dist

Black_prince [1.1K]

Answer:

he phase difference is π the destructive interference and the lujar is a still or silent place

Explanation:

This is a sound interference exercise where the amino difference is equal to the phase difference of the sound.

Δr / λ = ΔФ / 2π

Let's find the path difference

r₁ = 4m

r₂ = √ (4² + 3²) = 5 m

Δr = r₂ - r₁

Δr = 5-4 = 1m

Let's find the wavelength of the sound

v = λ f

λ = v / f

λ = 340/170

λ = 2m

Let's find the phase difference between the two waves

ΔФ = Δr 2π / λ

ΔФ = 1 2π / 2

ΔФ = π

Since the phase difference is π the destructive interference and the lujar is a still or silent place

4 0

3 years ago

a force of 9.0N is applied to a body at rest on a smooth horizontal surface. if the body has a mass of 18.0Kg and it moves in th

BaLLatris [955]

Explanation:

In this case a body of 18 kg is placed on the smooth surface .

The distance covered covered by the body in four seconds can be found by the relation S = u t + 1/2 a t²

Here S is the displacement , u is the initial velocity and a is the acceleration of the body . t is the time taken

In this case initial velocity u = 0 , because the body is at rest .

the acceleration is force/mass = 9/18 = 0.5 m/sec²

The values are substituted in the above equation

Thus S = 0 + 1/2 x 0.5 x ( 4 )² = 4 m

Therefore the body will move 4 m in four seconds

The work done = Force x displacement

= 9 x 4 = 36 J

The displacement in fourth second can be found by relation

S₄ = u + a/2 ( 2 n - 1 ) ; where n is the number of seconds , which is 4 in this case

Thus S₄ = 0 + 0.5/2 ( 2 x 4 - 1 ) = 3.5/2 = 1.75 m

Therefore the work done = 9 x 1.75 = 15.75 J

4 0

4 years ago

In each of the given pairs, choose which element will have the bigger atom. Give reasons for your choice. (a) Mg (atomic number

Dafna1 [17]

Answer:

Mg (atomic number 12)

K (atomic number 19)

Explanation:

The size of an atom is estimated in terms of its atomic radius.

The atomic radius is taken as half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance (d) between two nuclei in the solid - state of metals.

Across a period, atomic radii decrease progressively from left to right.
This is due to the progressive increase in the nuclear charge without increase in the number of electronic shells.
Down a group, atomic radii increase progressively due to the successive shells of electrons being added which have been compensated for by the increase in nuclear charge.

Cl is further right of Mg in the third period

K is below Na in the first group

3 0

3 years ago

Which of the following describes an isotope?

algol13

Answer:

2. atoms of an element that have the same number of protons and a different number of neutrons

Explanation:

Isotopes of an element is made up of atoms of an element that have the same number of protons and a different number of neutrons.

The number of protons are the positively charged particles in an atom

The number of neutrons are the uncharged particles.

Isotopy is the existence of two or more atoms of the same element having the same atomic number but different mass numbers due to the differences in the number of neutrons in their carious nuclei.

Isotopes have have the same electronic configuration and hence will have similar chemical properties. They only differ in their masses.

8 0

3 years ago

A child sets off the firecracker at a distance of 100 m from the family house. what is the sound intensity β100 at the house?

KATRIN_1 [288]

To solve this problem, we use the formula:

I100 / I1 = [P / 4π(100m)^2] / [P / 4π(1m)^2]

I100 / I1 = 1 / 100^2

I100 / I1 = 10^-4

Therefore the change in intensity from 1m to 100m in decibels is:

B100 – B1 = 10 log(10^-4) dB = -40 dB

So the intensity at 100m is calculated as:

B100 = B1 – 40 dB = 140 dB – 40 dB = 100 dB

Answer:

100 dB

6 0

3 years ago

Read 2 more answers