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just olya [345]
3 years ago
6

What is the total force of an object which has a mass of 150kg and is accelerating at 2m/s/s?

Physics
1 answer:
fredd [130]3 years ago
6 0

Answer:

\boxed {\boxed {\sf 300 \ Newtons }}

Explanation:

Force can be found by multiplying the mass by the acceleration.

F=ma

The mass is 150 kilograms and the acceleration is 2 meters per second per second, or 2 meters per square second.

m= 150 \ kg \\a= 2 \ m/s^2

Substitute the values into the formula.

F= 150 \ kg * 2 \ m/s^2

Multiply.

F= 300 \ kg*m/s^2

  • We know that 1 kilogram meter per square second is equal to 1 Newton.
  • Therefore our answer of 300 kg*m/s² is equal to 300 N

F= 300 \ N

The force of the object is <u>300 Newtons.</u>

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3 years ago
Question 7 (1 point)
ioda

Answer:

1150 secs

distance = speed x time

time = distance / speed

230,000 / 200 = 1150

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A) A mass spectrometer has a velocity selector that allows ions traveling at only one speed to pass with no deflection through s
KengaRu [80]

Answer:

(A). The speed of the ions is 1.2\times10^{6}\ m/s

(B). The radius of curvature of a singly charged lithium ion is 2.0\times10^{6}\ m

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Given that,

Electric field = 60000 N/C

Magnetic field = 0.0500 T

(A). We need to calculate the velocity

For no deflection

F_{E}=F_{B}

Eq=Bqv

v = \dfrac{E}{B}

v=\dfrac{60000}{0.0500}

v=1.2\times10^{6}\ m/s

(B). We need to calculate the radius

Using magnetic force balance by centripetal force

Bqv=\dfrac{mv^2}{r}

r=\dfrac{mv^2}{Bqv}

Put the value into the formula

r=\dfrac{1.16\times10^{-26}\times(1.2\times10^{6})^2}{0.0500\times1.6\times10^{-19}}

r=2.0\times10^{6}\ m

Hence, (A). The speed of the ions is 1.2\times10^{6}\ m/s

(B). The radius of curvature of a singly charged lithium ion is 2.0\times10^{6}\ m

6 0
3 years ago
Can you pickle a pickle? Like take a cucumber that's already pickled, can you then pickle that pickled cucumber?
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what type of question is that

6 0
3 years ago
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Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial spe
iris [78.8K]

Answer:

Explanation:

1.  V_{x} = V_{0} * cos\alpha ⇒ 16*cos32 ≈ 13.6 m/s (13.56)

2. V_{y} = V_{0} * sin\alpha ⇒ 16* sin32 ≈ 9.4 m/s

3. y_{max} = \frac{v_{0}^2*sin^2\alpha}{2g}= \frac{16^2*sin^232}{2*9.8} (the g (gravity) depends on the country but i'll take the average g which is 9.2m/s^2)

y_{max} ≈ 3.6677+1.5 ≈ 5.2m

4.  x_{max} = \frac{v_{0}^2*sin(2\alpha)}{g}=\frac{16^2*sin(2*32)}{9.8} ≈ 23.5m (23.47)

5. -

answer 4 could be wrong, not certain about that one and i don't know 5

3 0
3 years ago
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