We know that tangential acceleration is related with radius and angular acceleration according the following equation:
at = r * aa
where at is tangential acceleration (in m/s2), r is radius (in m) aa is angular acceleration (in rad/s2)
So the radius is r = d/2 = 1.2/2 = 0.6 m
Then at = 0.6 * 5 = 3 m/s2
Tangential acceleration of a point on the flywheel rim is 3 m/s2
I think i used calulater and it gives me 47.5
Answer:
Part a)

Part b)

Explanation:
As we know that by parallel axis theorem we will have

Part a)
here we know that for a stick the moment of inertia for an axis passing through its COM is given as

now if we need to find the inertia from its end then we will have



Part b)
here we know that for a cube the moment of inertia for an axis passing through its COM is given as

now if we need to find the inertia about an axis passing through its edge



Answer: F=3158N
Explanation:
Work is the product of force applied and the distance the object moves along the force applied. Work is measured in joules and the equation is as follows
W = F x d
So that F = W/d
F = 30000 J / 9.5m
F = ~3158 N