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Sergio039 [100]
3 years ago
13

Find each unit rate. Determine which is lower. Drag and drop the correct rate or letter into each of the boxes to complete the s

entences. Ingredient C: 1/5 cup for 3/4 serving or Ingredient D: 1/4 cup for 4/5 serving.
Mathematics
1 answer:
Contact [7]3 years ago
7 0

Answer:

4/15 < 5/16

Ingredient C < Ingredient D

Hence ingredient C has a lower cup per serving than ingredient D

Step-by-step explanation:

Given the unit rates :

C: 1/5 cup for 3/4 serving or Ingredient

D: 1/4 cup for 4/5 serving

C : 1/5 cup for 3/4 serving

1/5 ÷ 3/4

1/5 * 4/3

= 4 / 15

= 0.2667

D: 1/4 cup for 4/5 serving

1/4 ÷ 4/5

1/4 * 5/4

= 5 / 16

= 0.3125

5/16 > 4/15 ;

Ingredient C < Ingredient D

Hence ingredient C has a lower cup per serving than ingredient D

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Answer:

The expression is equivalent to 27 x⁹ y⁶.

Step-by-step explanation:

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2 years ago
Are 3(h+4) and 3h + 12 equivalent? Explain using the table from Question 4.
Kruka [31]
Yes because once you distribute the 3 in the first equation it turns it into 3h+12
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What is the solution to the system of equations?<br> O (-8,-4)<br> O(-4,-8)<br> O (44)<br> 0 (4-4)
Novay_Z [31]

Answer:

Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
Find the GCF of the given list.<br>x^17 y^3, x^4 y^3, x^5 y^5 ​
trasher [3.6K]

Answer:

the greatest common factor is 1.

Step-by-step explanation:

The factors of 3 are: 1, 3

The factors of 3 are: 1, 3

The factors of 4 are: 1, 2, 4

The factors of 5 are: 1, 5

The factors of 5 are: 1, 5

The factors of 17 are: 1, 17

Then the greatest common factor is 1.

7 0
1 year ago
Solve 12^x^2+5x-4 = 12^2x+6
faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

                    12^{x^{2}+5 x-4}=12^{2 x+6}

Since the base on both sides as ‘12’ are the same, we can write it as

                     x^{2}+5 x-4=2 x+6

                     x^{2}+5 x-2 x-4-6=0

                     x^{2}+3 x-10=0

Often, the value of x is easiest to solve by a x^{2}+b x+c=0 by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For a x^{2}+b x+c=0, the values of x which are the solutions of the equation are given by:

                       x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Where, a = 1, b = 3 and c = -10

                       x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}

                       x=\frac{-3 \pm \sqrt{9+40}}{2}

                       x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}

So, the solutions for ‘x’ are

                       x=\frac{-3+7}{2}=\frac{4}{2}=2

                       x=\frac{-3-7}{2}=\frac{-10}{2}=-5

The solutions for ‘x’ are 2 and -5

6 0
2 years ago
Read 2 more answers
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