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3 years ago

A cube has a length of 1.02 cm and a mass of .001012 kg what is its density

Chemistry

1 answer:

slega [8]3 years ago

8 0

Answer:

d = 9.5× 10⁻⁴ Kg/cm³

Explanation:

Given data:

Length of cube = 1.02 cm

Mass of cube = 0.001012 Kg

Density of cube = ?

Solution:

The length , height and width of cube is always same. Thus the volume of cube is,

Volume = length × height× width

Volume = 1.02 cm × 1.02 cm × 1.02 cm

Volume = 1.06 cm³

Density of cube:

d = 0.001012 Kg /1.06 cm³

d = 9.5× 10⁻⁴ Kg/cm³

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7. NH2CO2NH4(s) when heated to 450 K undergoes the following reaction to produce a system which reaches equilibrium: NH2CO2NH4(s

Taya2010 [7]

Answer:

Value of equilibrium constant is 0.0888

Explanation:

Both $NH_{3}$ and $CO_{2}$ are gaseous. Hence equilibrium constant depends upon partial pressures of $NH_{3}$ and $CO_{2}$ .

Initially no $NH_{3}$ and $CO_{2}$ were present.

Hence mole fraction of $NH_{3}$ and $CO_{2}$ at equilibrium can be calculated from coefficient of $NH_{3}$ and $CO_{2}$ in balanced equation.

Mole fraction of $NH_{3}$ = (number of moles of $NH_{3}$ )/(total number of moles of $NH_{3}$ and $CO_{2}$ ) = $\frac{2moles}{(2+1)moles}=\frac{2}{3}$

Mole fraction of $CO_{2}$ = (number of moles of $CO_{2}$ )/(total number of moles of $NH_{3}$ and $CO_{2}$ ) = $\frac{1moles}{(2+1)moles}=\frac{1}{3}$

Let's assume both $CO_{2}$ and $NH_{3}$ behaves ideally.

Therefore partial pressure of $NH_{3}$ , $P_{NH_{3}}= x_{NH_{3}}.P_{total}$ and P_{CO_{2}}= x_{CO_{2}}.P_{total}

Where x represents mole fraction

So, $P_{NH_{3}}=\frac{2}{3}\times 0.843atm=0.562atm$

$P_{CO_{2}}=\frac{1}{3}\times 0.843atm=0.281atm$

So, $K_{p}=P_{NH_{3}}^{2}.P_{CO_{2}}=(0.562)^{2}\times 0.281=0.0888$

4 0

3 years ago

Which statement is correct about the conclusions of historical events? A) Historical event conclusions can be tested using the s

BARSIC [14]

C is the correct answer I believe

4 0

3 years ago

Read 2 more answers

what is the structure of XeO2F2???i know its hybridization as sp3d but cannot quite understand its diagram in free space,help an

skelet666 [1.2K]

The shape of XeO₂F₂ is Trigonal bi-pyramidal see-saw tetrahedron (see attached pictures)
- As you said the hybridization of Xe here is sp³d so its geometry has to be Trigonal bi-pyramidal in which F atom located on axial positions but for the final shape we exclude lone pair on Xe to give see-saw shape (see second picture)
- Remember that we have 5 pairs (4 bond pairs + 1 lone pair) and we have to place lone pair at equatorial position.