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malfutka [58]
3 years ago
6

a flashlight bulb with a potential difference of 6.0 v across it has a resistance of 8.0 how much current is the bulb filament

Physics
1 answer:
Andreas93 [3]3 years ago
3 0

Answer:

<em>I = 0.75 Amp</em>

Explanation:

<u>Ohm's Law</u>

Ohm's law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points. The constant of proportionality is called the Resistance (R) of the conductor.

The formula can be expressed as:

V = I.R

The intensity of the current through a resistor can be calculated by solving the equation for I:

\displaystyle I=\frac{V}{R}

A flashlight bulb is an example of a resistor with the specific task to emit light when it's hot enough.

The potential difference (or voltage) is V=6 V and the resistance is R=8Ω, thus the current is:

\displaystyle I=\frac{6~V}{8~\Omega}

I = 0.75 Amp

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Answer:

The ability to do work is energy

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Refer to Concept Simulation 4.4 for background relating to this problem. The drawing shows a large cube (mass = 28.9 kg) being a
Usimov [2.4K]

Answer:

smallest magnitud is P=33.3 N

Explanation:

We are analyze the situation as an external force is applied and there is a friction force. We have a problem with Newton's second law.

          F = ma

As the two blocks go together they must have the same acceleration, so we can calculate this for the entire system

        P = (m1 + m2) a

        a = P / (m1 + m2)

In this case there is no friction force because the small block does not touch the ground.

In order to calculate the friction force, we must analyze each system component separately.

The large block on the X axis has an applied P force and as it moves feels a force from the small block.  In the Y axis has the weight (W1) and the reaction to normal (N1)

For the small block on the X axis, the force it feels is the thrust of the large block, note that this is an action and reaction force between the two blocks, it is the same definition we have of the normal one, so we can call this force (N)

Y axis it has the weight (W2) down, the force of friction (fr) that opposes the movement, so it is directed upwards. we write these equations

       N = m2 a

       fr -W2 = 0    

       fr = W2

       

The definition of friction force is

       fr = μ N

       

Let's replace and calculate

       μ (m2 a) = m2 g

       μ (P / (m1 + m2)) = g

       P = g /μ  (m1 + m2)

Let's calculate the value of this force

       P = 9.8 / 0.710 (28.9 +4.4)

       P = 13.80 (33.3)

       P = 33.3 N

This is the minimum friction force that prevents the block from sliding down

6 0
3 years ago
A man holding a rock sits on a sled that is sliding across a frozen lake (negligible friction) with a speed of 0.460 m/s. The to
xz_007 [3.2K]

Answer:

= 0.417 m/s

Explanation:

Momentum before throwing the rock: m*V = 95.0 kg * 0.460 m/s

= 44.27 N*s  

A) man throws the rock forward

mass of rock m1 = 0.310 kg

V1 = 15.5 m/s, in the same direction of the sled with the man

sled and man:

m2 = 95 kg - 0.310 kg = 94.69 kg

v2 = ?

Conservation of momentum:

momentum before throw = momentum after throw

44.27N*s = 0.310kg * 15.5m/s + 94.69kg*v2

⇒ v2 = [44.27 N*s - 0.310 * 15.5N*s ] / 94.69 kg

= 0.417 m/s

6 0
4 years ago
Read 2 more answers
1 A truck covers a distance of 580km in 7 hours - Calculate<br>the velocity in km/hr​
Digiron [165]

Answer:

82.86

Explanation:

to find velocity you displacement by time

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Two long, parallel wires are separated by 2.0 m. Each wire has a 28-A current, but the currents are in opposite directions. Part
BlackZzzverrR [31]

Given Information:  

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Required Information:  

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Answer:  

B = 12x10⁻⁶ T

Step-by-step explanation:  

Biot-Savart Law is given by  

B = μ₀I/2πr

Where μ₀ is the permeability of free space, I is the current flowing through the wire and B is the magnitude of the magnetic field produced.  

We are asked to find the magnetic field midway between the wires so r/2 = 1

B = 4πx10⁻⁷*28/2π*1

B = 6x10⁻⁶ T

since the same amount of current flows in both wires therefore, equal amount of magnetic field will be produced in both wires

B = 2*6x10⁻⁶ T

B = 12x10⁻⁶ T

Therefore, the net magnetic field midway between the two wires is 12x10⁻⁶ T.

3 0
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